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2 years ago

A negative charge of -6.0x10-6 C exerts an

1 answer:

7 0

The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C

<h3>Coulomb's law equation </h3>

F = Kq₁q₂ / r²

Where

F is the force of attraction
K is the electrical constant
q₁ and q₂ are two point charges
r is the distance apart

<h3>How to determine the second charge </h3>

Charge 1 (q₁) = –6×10¯⁶ C
Electric constant (K) = 9×10⁹ Nm²/C²
Distance apart (r) = 0.05 m
Force (F) = 65 N

Charge 2 (q₂) =?

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Divide both side by Kq₁

q₂ = Fr² / Kq₁

q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)

q₂ = +3.0×10¯⁶ C (since the force is attractive)

Learn more about Coulomb's law:

brainly.com/question/506926

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