Answer:
F = 309.24 N
Explanation:
Given that,
Charge on a strom cloud, q₁ = 0.055 C
The charge gained by the top of a tree, q₂ = -0.006 C
The cloud moves to 98 meters above the tree.
We need to find the amount of force between the cloud and the tree. The electrical force between two charges is given by :
So, the force between the cloud and the tree is equal to 309.24 N.
Angling of the focal track of the anode to create a large actual focal spot and a smaller effective focal spot describes the line focus principle
<h3>
What is the line focus principle?</h3>
The line focus principle states that as the anode angle is reduced, the actual focal spot also becomes small but the heat loading is increased.
It also explains the relationship between the anode surface and the effective focal spot size.
As a result of this, by angling the target, effective area of the target is made much smaller that the actual area of electron interaction.
Hence, angling of the focal track of the anode to create a large actual focal spot and a smaller effective focal spot describes the line focus principle.
Learn more about line focus principle here:
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Answer:
= 1227.9K
Explanation:
Given that,
D₀ = 4.0 x 10⁻⁵ m²/s,
Qd = 230,000 J/mol,
D = 6.48 x 10⁻¹⁵ m²/s
Gas constant R = 8.31 J/mol-K
T = 
= 
= 
= 1227.93K
≅1227.9K
First, let us derive our working equation. We all know that pressure is the force exerted on an area of space. In equation, that would be: P = F/A. From Newton's Law of Second Motion, force is equal to the product of mass and gravity: F = mg. So, we can substitute F to the first equation so that it becomes, P = mg/A. Now, pressure can also be determined as the force exerted by a fluid on an area. This fluid can be measure in terms of volume. Relating volume and mass, we use the parameter of density: ρ = m/V. Simplifying further in terms of height, Volume is the product of the cross-sectional area and the height. So, V = A*h. The working equation will then be derived to be:
P = ρgh
This type of pressure is called the hydrostatic pressure, the pressure exerted by the fluid over a known height. Next, we find the literature data of the density of seawater. From studies, seawater has a density ranging from 1,020 to 1,030 kg/m³. Let's just use 1,020 kg/m³. Substituting the values and making sure that the units are consistent:
P = (1,020 kg/m³)(9.81 m/s²)(11 km)*(1,000 m/1km)
P = 110,068,200 Pa or 110.07 MPa
