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3 years ago

13

What is your theory on frame of reference?

1 answer:

____ [38]3 years ago

8 0

What is your theory on frame of reference?

Answer:

It is the idea of seeing something from a different perspective

Explanation:

Hope this helps!

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Need help with number <br> 50 <br> PLEASE HELP! Show all work please!

Pavel [41]

Answer:50 is b

Explanation:

v = 34757

6 0

3 years ago

You are riding your bike to the mall. You travel the first mile in 10 minutes. The last mile takes you 15 minutes. This is an ex

ratelena [41]

I am pretty sure that when you travel the first mile in 10 minutes. The last mile takes you 15 minutes. This is an example of negative acceleration. I consider this to be correct because <span>the second mile was slower. Hope you will agree with me. Regards!</span>

4 0

3 years ago

Read 2 more answers

I need help :(((((((((((

Alex Ar [27]

Answer:

4- false

5- false (i think..)

Explanation:

6 0

3 years ago

The space shuttle releases a satellite into a circular orbit 630 km above the Earth.

solniwko [45]

Answer:

7,539 m/s

Explanation:

Let's use this equation to find the gravitational acceleration of this space shuttle:

$\displaystyle g=\frac{GM}{r^2}$

We know that G is the gravitational constant: 6.67 * 10^(-11) Nm²/kg².

M is the mass of the planet, which is Earth in this case: 5.972 * 10^24 kg.

r is the distance from the center of Earth to the space shuttle: radius of Earth (6.3781 * 10^6 m) + distance above the Earth (630 km → 630,000 m).

Plug these values into the equation:

$\displaystyle g=\frac{(6.67\cdot 10^-^1^1 \ Nm^2kg^-^2)(5.972\cdot 10^2^4 \ kg)}{[(6.3781\cdot 10^6 \ m)+(630000 \ m)]^2}$

Remove units to make the equation easier to read.

$\displaystyle g=\frac{(6.67\cdot 10^-^1^1 )(5.972\cdot 10^2^4 )}{[(6.3781\cdot 10^6)+(630000 )]^2}$

Multiply the numerator out.

$\displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(6.3781\cdot 10^6)+(630000 )]^2}$

Add the terms in the denominator.

$\displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(7008100)]^2}$

Simplify this equation.

$\displaystyle g=8.11045189 \ \frac{m}{s^2}$

The acceleration due to gravity g = 8.11045189 m/s². Now we use the equation for acceleration for an object in circular motion which contains v and r.

$\displaystyle a = \frac{v^2}{r}$

a = g, v is the velocity that the space shuttle should be moving (what we are trying to solve for), and r is the radius we had in the previous equation when solving for g.

Plug these values into the equation and solve for v.

$\displaystyle 8.11045189 \ \frac{m}{s^2} = \frac{v^2}{7008100 \ m}$

Remove units to make the equation easier to read.

$\displaystyle 8.11045189 = \frac{v^2}{7008100}$

Multiply both sides by 7,008,100.

$56838857.89=v^2$

Take the square root of both sides.

$v=7539.154985$

The shuttle should be moving at a velocity of about 7,539 m/s when it is released into the circular orbit above Earth.

5 0

3 years ago

A flea walking along a ruler moves from the 45 cm mark to the 27 cm mark. It does this in 3 seconds. What is the speed? What is

ad-work [718]

Answer:

Explanation:

In the calculation of distance we do not take into account the direction of movement .So only magnitude of movement is taken care of.

On the other hand , in respect of displacement , we take into account even direction of movement along with magnitude.

Distance covered by flea = 45 - 27 = 18 cm

Displacement by flea = 27 - 45 = - 18 cm

Speed = Distance covered / time

= 18 / 3 = 6 cm / s

Velocity = - 18 / 3 = - 6 cm /s.

3 0

3 years ago