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Llana [10]
2 years ago
15

Help with this question plz and show how you got it :) tysm!

Physics
1 answer:
spayn [35]2 years ago
5 0
The hardest part of the job is to find the right formula to use, and write it down. You've already done that ! The rest is just turning the crank until an answer falls out.

You wrote. E = m g h.
Beautiful.
Now divide each side by (g h), and you'll have the formula for mass:

m = E / (g h).

You know all the numbers on the right side. Just pluggum in, do the arithmetic, and you'll have the mass.
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A drone flies 8 m/s due East with respects to the wind. The wind is blowing 6 m/s due North with respects to the ground. What is
vekshin1

Answer:

B. 10m/s

Explanation:

If a drone flies 8 m/s due East with respects to the wind and the wind is blowing 6 m/s due North, the speed of the drone with respect to the ground is its displacement.

Displacement is calculated using Pythagoras theorem.

d² = 8²+6²

d² = 64+36

d² = 100

Square root both sides

√d² = √100

d = 10m/s

Hence the distance of the drone with respect to the ground is 10m/s

Option B is correct

8 0
3 years ago
Define the term antinode and explain how standing waves form.
Otrada [13]

Answer:

standing wave, also called stationary wave, combination of two waves moving in opposite directions, each having the same amplitude and frequency.

For oppositely moving waves, interference produces an oscillating wave fixed in space. fixed nodes in a standing wave. Location of fixed nodes in a standing wave

these are the points that undergo the maximum displacement during each vibrational cycle of the standing wave. In a sense, these points are the opposite of nodes, and so they are called antinodes. A standing wave pattern always consists of an alternating pattern of nodes and antinodes

Explanation:

6 0
3 years ago
An iron sphere of radius 0.18m has mass 190 kg. Calculate the density of the iron
Slav-nsk [51]
  • radius=r=0.18m

Volume:-

\\ \sf\rightarrowtail \dfrac{4}{3}\pi r^3

\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.18)^3

\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.005832)

\\ \sf\rightarrowtail 0.024m^3

  • Mass=190kg

Density:-

\\ \sf\rightarrowtail \dfrac{Mass}{Volume}

\\ \sf\rightarrowtail \dfrac{190}{0.024}

\\ \sf\rightarrowtail 7916.67kg/m^3

8 0
2 years ago
if you push a box a distance of 2000 meters with a force of 1 newton, how many calories have you used
kap26 [50]
Note that
1 J = 0.239 cal

By definition,
Work = Force x Distance

Therefore work done is
W = (1 N)*(2000 m) = 2000 J

In calories,
W = (2000 J)*(0.239 cal/J) = 478 cal

Answer: 478 calories

4 0
3 years ago
a 1500.0 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car m
padilas [110]

Acceleration of the car is 3.375 m/s² and the force of the car moving forward is 5062.5 N

Explanation:

  • Acceleration is the rate of change of velocity.
  • It is given by the equation, a = change in velocity/time

Here, velocity changes from 0 to 27 m/s and time = 8

⇒ Acceleration = 27 - 0/8 = 27/8 = 3.375 m/s²

  • Force is calculated by the equation, F = Mass × Acceleration
  • This is based on Newton's second law of motion.

Here, mass of the car = 1500 kg and a = 3.375 m/s²

⇒ Force = 1500 × 3.375 = 5062.5 N

4 0
3 years ago
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