Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1
Answer:
a = 31.7
c = 39.1
Step-by-step explanation:
tan54 = a / 23
a = 23 * tg54
a = 31.7
sin54 = 31.7 / c
c = 31.7 / sin54
c = 39.1
:)
Answer:
3(25π/2) + 100 = 217.8097
Step-by-step explanation:
Let us suppose the width is x feet
the length is given 12 feet
Perimeter of teh garden = 2( Length + width )= 2( 12+ x)
Fencing required = perimeter of garden
36 = 2( 12+x)
36 = 2*12 + 2x
36 = 24 + 2x
36-24 = 2x
12 = 2x
12/2 = x
6 = x
Width = x feet = 6 feet .Answer .
Answer:
378$
Step-by-step explanation:
since u got 700ft^2 you would multiply 700 with 0.54 and get 378$