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Nookie1986 [14]

2 years ago

5

Calculate the distance between the points M=(-9, 8) and G=(-1, 3) in the coordinate plane.

1 answer:

ziro4ka [17]2 years ago

6 0

Answer:

9.4339811320566

Step-by-step explanation:

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Can anyone help me with this problem?

Katen [24]

A because -2 -3 -4 ext are less than -1

6 0

2 years ago

Find the coordinates of the midpoint of the segment given its endpoints.

Vesna [10]

Answer:

(2, 2 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ $\frac{1}{2}$ (x₁ + x₂ ) , $\frac{1}{2}$ (y₁ + y₂ ) ]

Here (x₁, y₁ ) = (A(5, 8) and (x₂, y₂ ) = B(- 1, - 4) , thus

midpoint = [ $\frac{1}{2}$ (5 - 1), $\frac{1}{2}$ (8 - 4 ) ] = (2, 2 )

6 0

2 years ago

On a fishing excursion, jeannie keeps 1/4 of the fish she catches and releases the remainder of the fish back into the lake. if

postnew [5]

To find 1/3 of 3/4 we divide the fraction by 3 which is equal to 1/4 or alternatively we can multiply the denominator by 3 which gives us 3/12 (1/4=3/12)
So 3/12 of the realesed fish are trout

To find 2/3 of 1/4 we need to first divide 1/4 by 3 which is equal to multiplying the denominator times 3 which gives us 1/12 and then we multiply by 2 which gives us 2/12
So 2/12 of the kept fish are trout

To find the total amount we add 2/12 and 3/12
3/12+2/12= 5/12

ANSWER:
5/12 of the fish she catches are trout

7 0

2 years ago

A magazine subscription runs several promotions. Customers can choose from the following deals:

icang [17]

1.8461 diveded 12/86

7 0

2 years ago

5. Mis the midpoint of CD. C has coordinates (-1,-1) and

lana66690 [7]

Answer/Step-by-step Explanation:

4. Midpoint (M) of AB, for A(-2, -3) and B(1, 2) is given as:

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Let $A(-2, -3) = (x_1, y_1)$

$B(1, 2) = (x_2, y_2)$

Thus:

$M(\frac{-2 + 1}{2}, \frac{-3 + 2}{2})$

$M(\frac{-1}{2}, \frac{-1}{2})$

5. Given M(3, 5) as midpoint of CD, and C(-1, -1),

let $C(-1, -1) = (x_2, y_2)$

$D(?, ?) = (x_1, y_1)$

$M(3, 5) = (\frac{x_1 +(-1)}{2}, \frac{y_1 +(-1)}{2})$

Rewrite the equation to find the coordinates of D

$3 = \frac{x_1 - 1}{2}$ and $5 = \frac{y_1 - 1}{2}$

Solve for each:

$3 = \frac{x_1 - 1}{2}$

$3*2 = \frac{x_1 - 1}{2}*2$

$6 = x_1 - 1$

$6 + 1= x_1 - 1 + 1$

$7 = x_1$

$x_1 = 7$

$5 = \frac{y_1 - 1}{2}$

$5*2 = \frac{y_1 - 1}{2}*2$

$10 = y_1 - 1$

$10 + 1= y_1 - 1 + 1$

$11 = y_1$

$y_1 = 11$

Coordinates of D is (7, 11)

7 0

2 years ago