Answer:
a)Patm=135.95Kpa
b)Pabs=175.91Kpa
Explanation:
the absolute pressure is the sum of the water pressure plus the atmospheric pressure, which means that for point a we have the following equation
Pabs=Pw+Patm(1)
Where
Pabs=absolute pressure
Pw=Water pressure
Patm=
atmospheric pressure
Water pressure is calculated with the following equation
Pw=γ.h(2)
where
γ=especific weight of water=9.81KN/M^3
H=depht
A)
Solving using ecuations 1 y 2
Patm=Pabs-Pw
Patm=185-9.81*5=135.95Kpa
B)
Solving using ecuations 1 y 2, and atmospheric pressure
Pabs=0.8x5x9.81+135.95=175.91Kpa
Answer:
Equilibrium Concentration = 0.105mg/kg
Explanation:
Let initial concentration be C₀
S(aq) at initial = C₀ , S(s) at initial = 0
S(aq) at equilibrium = C₀ - Xe , S(s) at equilibrium = Xe
Xe = 1312.5 mg/kg
At equilibriuim Kd = [S(s)]/[S(aq)]
12500 = 1312.5/(C₀ - 1312.5)
C₀ = 1312.605 mg/kg
Equilibrium Concentration = 1312.605 - 1312.5 = 0.105mg/kg
Answer:
I think you forgot the image.
Explanation:
Answer:
The concentration in mg/L equals 0.01 mg/L
Explanation:
Since the concentration is given as 10 parts per billion
We know that
1 part per billion equals 0.001 mg/L
Thus 10 parts per billion concentration equals