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dolphi86 [110]
3 years ago
15

A car drives 90 meters north, then turns around and drives 120 meters south. What was its displacement and distance?

Physics
1 answer:
Rufina [12.5K]3 years ago
3 0

Answer:

displacement= 30 m towards south, distance= 210m

Explanation:

Distance (scalar quantity) how much ground an object has covered.

Displacement (vector quantity) refers to how far out of place an object is it is the object's overall change in position.

Basically meaning for displacement the directions will be very key

D for Displacement

D= D1+D2

D=  120 (S) + 90 m (N)

Must be in same direction

D= 120 (S) + (-90 m) (S)

D= 30 m (S)

and for distance you are simply just adding how much distance they have covered

so d= d1+d2

d= 90m + 120m

d= 210m

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Two football players collide head-on in midair while trying to catch a thrown football. The first player is 98.5 kg and has an i
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Answer:

v_f=0.825m/s

Explanation:

We must use conservation of linear momentum before and after the collision, p_i=p_f

Before the collision we have:

p_i=p_1+p_2=m_1v_1+m_2v_2

where these are the masses are initial velocities of both players.

After the collision we have:

p_f=(m_1+m_2)v_f

since they clong together, acting as one body.

This means we have:

m_1v_1+m_2v_2=(m_1+m_2)v_f

Or:

v_f=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Which for our values is:

v_f=\frac{(98.5kg)(6.05m/s)+(119kg)(-3.5m/s)}{(98.5kg)+(119kg)}=0.825m/s

7 0
3 years ago
Water flows over a section of Niagara Falls at the rate of 1.4 × 106 kg/s and falls 49.8 m. How much power is generated by the f
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Answer:

Power= 6.84×10⁸ W

Explanation:

Given Data

Niagara falls at rate of=1.4×10⁶ kg/s

falls=49.8 m

To find

Power Generated

Solution

Regarding this problem

GPE (gravitational potential energy) declines each second is given from that you will  find much the kinetic energy of the falling water is increasing each second.

So power can be found by follow

Power= dE/dt = d/dt (mgh)

Power= gh dm/dt

Power= 1.4×10⁶ kg/s × 9.81 m/s² × 49.8 m

Power= 6.84×10⁸ W  

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3 years ago
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To transfer electric current from one point to another

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Option D

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