Where r is the radius of balloon.
Here mass of woman = 68 kg
Mass of air displaced by a balloon with volume V = 1.29*V
Mass of helium inside balloon = 0.178*V
Total mass to be lifted by balloon = 68 +0.178*V
Buoyant force = 1.29V-0.178V=1.112V
So we have 1.112 V = 68+ 0.178*V
0.934 V = 68
V = 72.81
\frac{4}{3} \pi r^{3}[/tex]= 72.81
r = 2.59 m
So radius of helium balloon = 2.59 m
Answer:
Impulse is 1.239 kg.m/s in upward direction
Explanation:
Taking upward motion as positive and downward motion as negative.
Downward motion:
Given:
Mass of ball (m) = 0.150 kg
Displacement of ball (S) = -1.25 m
Initial velocity (u) = 0 m/s
Acceleration is due to gravity (g) = -9.8 m/s²
Using equation of motion, we have:
Since, the motion is downward, final velocity must be negative. So,
Upward motion:
Given:
Displacement of ball (S) = 0.665 m
Initial velocity () = 4.95 m/s(Upward direction)
Acceleration is due to gravity (g) = -9.8 m/s²
Using equation of motion, we have:
Since, the motion is upward, final velocity must be positive. So,
Now, impulse is equal to change in momentum. So,
Impulse = Final momentum - Initial momentum
Therefore, the impulse given to the ball by the floor is 1.239 kg.m/s in upward direction.