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kotegsom [21]
3 years ago
7

Two of the angles in a triangle measure 149° and 90. What is the measure of the third angle?

Mathematics
1 answer:
Inga [223]3 years ago
7 0
Third angle =180° - (149° + 9°)
= 22°
Thanks me if is correct!
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Determine whether the relation is a function (-4,12), (1,6), (4, -2), (7-8), (10,-14)
erastovalidia [21]

No,it is not a function.

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3 years ago
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Abigail made a quilt that has an area of 4800 square inches. The length of the quilt is 1 1/3 times the width of the quilt. What
mafiozo [28]

Answer:

L=132.66

36.18=W

Step-by-step explanation:

length=L

width=W

Area=A

A=L×W

L=11/3W

4800=11/3W×W

4800=11/3W²

3/11·4800=11/3W²·3/11

√1309.1=√W²

36.18=W

L=11/3×36.18

L=132.66

All answers are approximated.




6 0
3 years ago
5x + 10 = 20
Andrei [34K]

To solve for <em>x</em>, we must first isolate the term containing <em>x</em> which in this problem is 5x.

Since 10 is being added to 5x, we subtract 10 from both sides of the equation to isolate the 5x.

On the left, the +10 and -10 cancel out and on the right, 20 - 10 is 10 and we have 5x = 10.

Now we can finish things off by just dividing both sides of the equation by 5. On the left the 5's cancel and on the right, 10 divided by 5 is 2 so <em>x = 2</em>.

4 0
3 years ago
A wireless phone company determines that 12 out of every 350 Model A phones are returned because of a defective screen. If the c
Len [333]
I think it would be 66
8 0
3 years ago
Real World Scenario:
iragen [17]

The distance of a train from the city depends on the speed, the time of

travel, and direction of motion of the train.

Correct responses:

  • Distance Train A is from the city: <u>750 - 75·t</u>
  • Distance Train B is from the city: 50·t
  • After <u>six</u> hours, the two trains are the same distance from the city
  • At that time both trains will be <u>300</u> miles away

1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours

2) At time period, t > 6 hours

3) 250 miles

<h3>Method used to find the above response</h3>

Given:

The distance of train A from the city = 750 miles

Speed of train A = 75 mph

Time at which Train B leaves the city = When Train A is 750 miles from the city

Speed of Train B = 50 mph

Solution:

The equations are;

  • Distance of Train A from the city is; <u>x₁ = 750 - 75·t</u>
  • Distance of Train B from the city is <u>x₂ = 50·t</u>

When the train are the same distance from the city, we have;

750 - 75·t = 50·t

750 = 50·t + 75·t = 125·t

Therefore;

  • t = \mathbf{\dfrac{750}{125}} = 6

The time it takes the two trains to be the same distance from the city is 6 hours.

Which gives;

  • After <u>6</u> hours, the two trains are the same distance from the city.

The distance the trains will be after 6 hours is therefore;

750 - 75 × 6 = 300

The distance of the trains from the city after 6 hours = 300 miles

Therefore, we have;

  • At that time both trains will be <u>300</u> miles away

1) The time period Train A is further from the city is before the first 6 hours elapse; <u>0 hours ≤ t < 6 hours</u>

2) The Train B is further from the city after 6 hours of its departure from the city; <u>t > 6 hours</u>

3) The distance of Train A from the city after 4 hours is given as follows;

x₁ = 750 - 75 × 4 = 450

x₁ = 450 miles

The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200

x₂ = 200 miles

Therefore;

  • The distance between the trains after 4 hours = 450 miles - 200 miles = <u>250 miles</u>

Learn more about distance and time relationship equation here:

brainly.com/question/10804931

3 0
2 years ago
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