A motor spins upward the flywheel with a persistent torque
of 50N⋅m.
What time does it take the flywheel to get to the top speed?
From the equation:
Tj = J*dω/dt
you can get the two equations:
Δt1= J1*Δω/Tj = 240*125.66/50 = 603.17 sec
Δt2= J2*Δω/Tj = 120*125.66/50 = 301.58 sec
Answer: P = 36.75W
The additional power needed to account for the loss is 36.75W.
Explanation:
Given;
Mass of the runner m= 60 kg
Height of the centre of gravity h= 0.5m
Acceleration due to gravity g= 9.8m/s
The potential energy of the body for each step is;
P.E = mgh
P.E = 60 × 9.8 × 0.5
PE = 294J
Since the average loss per compression on the leg is 10%.
Energy loss = 10% (P.E)
E = 10% of 294J
E = 29.4J
To calculate the runner's additional power
given that time per stride is = 0.8s
Power P = Energy/time
P = E/t
P = 29.4J/0.8s
P = 36.75W
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22N to the right and 13N to the left
Forces are in opposite directions so you subtract the bigger force from the smaller force
Magnitude of force= 22N -13N
= 9N
net force direction is to the right
Answer:
Average speed = 0.0075 m/s
Average velocity = 0.0025 m/s along forward direction
Explanation:
Speed is the ratio of distance and time and velocity is the ratio of displacement and time.
Distance traveled = 10 + 5 = 15 cm = 0.15 m
Displacement = 10 - 5 = 5 cm = 0.05 m
Time = 20 seconds
Average speed = 0.0075 m/s
Average velocity = 0.0025 m/s along forward direction
