Answer:
The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the difference between population means is:
The information provided is as follows:
The critical value of <em>z</em> for 98% confidence level is,
Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:
Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).
Answer:
you will multiply the new price plus the original price
Answer:
yes.
Step-by-step explanation:
because -8 absolute value is 8
Answer:
6.4 minutes
Step-by-step explanation:
The question gave us the following details:
Average speed = 60mph
Time spent on trip = 8 hours
Average speed of express train on way back = 75mph
T = distance/speed
D = distance
V = speed
T = d/v
d = v(t)
d = 60 x 8
= 480
Such that
480/75
= 6.4 hours.
That is 6 hours 40 minutes is the length of time it would take on the trip home.
Thank you!
Answer: 200x^2y+640x^2+1010xy+3232x-2380y-7616
Step-by-step explanation:
((8x−14)(5y+16))(5x+34)
((8x−14)(5y+16))(5x)+((8x−14)(5y+16))(34)
200x2y+640x2−350xy−1120x+1360xy+4352x−2380y−7616
200x2y+640x2+1010xy+3232x−2380y−7616
