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OverLord2011 [107]
3 years ago
15

Study the diagram and calculate the effort required to balance the load​

Physics
1 answer:
Lisa [10]3 years ago
6 0

Answer:

Solution given;

load =600N

effort=?

load distance: 0.6m

effort distance;2.6m

we have

load *load distance :effort *effort distance

0.6*600=effort *2.6

360/2.6=effort

effort:138.46N

<u>R</u><u>e</u><u>q</u><u>u</u><u>i</u><u>r</u><u>e</u><u>d</u><u> </u><u>e</u><u>f</u><u>f</u><u>o</u><u>r</u><u>t</u><u> </u><u>i</u><u>s</u><u> </u><u>1</u><u>3</u><u>8</u><u>.</u><u>5</u><u>N</u><u>.</u>

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PLS ANSWER FAST THIS IS TIMED TEST AND WILL GIVE BRAINLY!!!
mylen [45]

Answer:

mass is 5 kg

Explanation:

F=m/a

M=f/a

F=5000

a=1000

5000/1000=5

6 0
3 years ago
Which has more momentum: a 20,000 kg cement truck traveling at 5 m/s or a 1000 kg race car traveling at 90 m/s
Maurinko [17]

Hi there!

Recall the equation for momentum:
\large\boxed{p = mv}

p = linear momentum (kgm/s)
m = mass (kg)

v = velocity (m/s)

We can calculate each object's momentum and compare.

Cement truck:
p = 20000 \cdot 5 = 100000kg\frac{m}{s}

Race car:
p = 1000 \cdot 90 = 90000 kg\frac{m}{s}}

<u>Since 100,000 > 90,000, the cement truck has the greater momentum.</u>

8 0
3 years ago
Suppose that a parallel-plate capacitor has circular plates with radius R = 25 mm and a plate separation of 4.7 mm. Suppose also
ozzi

Answer:

a) B_{max} = 1.784*10^{-12}

Explanation:

Given paraeters are:

R = 25 cm

d = 4.7 mm

f = 60 Hz

V_m = 160 V

a) V = V_msin(2\pi ft)

Where f = 60 Hz and V_m = 160 V

E =V/d= \frac{V_msin(2\pi ft)}{d}

For r = R

A = \pi R^2

Since \Phi_E = EA

\Phi_E=\frac{\pi R^2V_msin(2\pi ft) }{d}

From Ampere's Law:

\int B.ds = \mu_0\epsilon_0\frac{d\Phi_E}{dt} + \mu_0I_{encl} where I_{encl}=0

So at r = R,

B.2\pi R = \mu_0\epsilon_0\frac{d\Phi_E}{dt}\\B.2\pi R = \mu_0\epsilon_0\frac{2\pi^2fR^2V_mcos(2\pi ft)}{d}\\B = \frac{\mu_0\epsilon_0\pi fRV_mcos(2\pi ft)}{d}

For maximum B, cos(2πft) = 1. Hence,

B_{max}=\frac{\mu_0\epsilon_0\pi fRV_m}{d}=\frac{4\pi*10^{-7}*8.85*10^{-12}*\pi*60*0.025*160}{4.7*10^{-3}}=1.784*10^{-12} T

b) From r = 0 to r = R = 0.025 m, by Ampere's Law, the equation will be:

B = \frac{\mu_0\epsilon_0\pi fR^2V_m}{rd}

From r = R = 0.025 m to r = 0.1 m, by Ampere's Law, the equation will be:

B = \frac{\mu_0\epsilon_0\pi fRV_m}{d}

The plot is given in the attachment.

5 0
4 years ago
Someone please help!! Will mark brainliest
11111nata11111 [884]

Answer:

d.

Explanation:

the arrow is starts at 0,0 and ends at 2,2

5 0
3 years ago
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What services do plants provide? Select the three that apply.
Irina18 [472]

The answer to this is B, C, and D. hope this helped

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3 years ago
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