Each BB 0.349 grams and 5.386 grains. 349 mg & 5.386 grains each steel BBs.
Answer:
n= 16021.03 slaps
Explanation:
Using law of Energy conservation
E_{thermal}= Kinetic energy of hand
⇒
m_h= mass of the hand = 0.4 kg
v_h= velocity of the hand = 10 m/s
n= number of slaps
c= 4180 J/Kg °C
m= mass of chicken = 1 kg
Assuming all the energy of hand goes into chicken
Given Ti=0°C and T_f= 170 F= 76.66°C
Now putting the values in above equation to get n

n= 16021.03 slaps
Answer:
The Moon blocks the suns light from hitting the surface of the earth
The force on the layer will be equivalent to the weight of water on it. This is given by:
F = mg; m is the mass of water and g is the acceleration due to gravity.
Answer: The unpolarized light's intensity is reduced by the factor of two when it passes through the polaroid and becomes linearly polarized in the plane of the Polaroid. When the polarized light passes through the polaroid with the plane of polarization at an angle
with respect to the polarization plane of the incoming light, the light's intensity is reduced by the factor of
(this is the Law of Malus).
Explanation: Let us say we have a beam of unpolarized light of intensity
that passes through two parallel Polaroid discs with the angle of
between their planes of polarization. We are asked to find
such that the intensity of the outgoing beam is
. To solve this we follow the steps below:
Step 1. It is known that when the unpolarized light passes through a polaroid its intensity is reduced by the factor of two, meaning that the intensity of the beam passing through the first polaroid is

This beam also becomes polarized in the plane of the first polaroid.
Step 2. Now the polarized beam hits the surface of the second polaroid whose polarization plane is at an angle
with respect to the plane of the polarization of the beam. After passing through the polaroid, the beam remains polarized but in the plane of the second polaroid and its intensity is reduced, according to the Law of Malus, by the factor of
This yields
. Substituting from the previous step we get

yielding

and finally,
