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katrin2010 [14]
4 years ago
7

Please help...

Physics
2 answers:
zhuklara [117]4 years ago
5 0

Answer:

Option A. Emotions affect your memory as memories with strong emotional attachments are easier to recall than other memories.

Explanation:

A memory is the faculty by which the mind stores and remembers information and experiences. Psychologists believe that emotions play a determining role in whether we can recall or not a memory or a past experience at the time we try to revisit it. It is always easier to recall a memory that has an emotional aspect to it within ourselves, rather than one that does not. That is why when recalling a memory we often experience the same emotion we felt when living that moment, because emotionally charged situations can lead us to create a longer lasting memories.

kolbaska11 [484]4 years ago
3 0
I would say memories with strong emotional attachments are easier to recall than other memories.. Hope that helps !
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A same-size iron ball and wooden ball are dropped simultaneously from a tower and reach the ground at the same time. The iron ba
Papessa [141]

Answer:

momentum of iron ball is greater than wooden ball

Explanation:

when metal ball (iron ball) and wooden drop are drop from same elevation and reaching the ground after same time. at this position the iron ball has greater momentum than wooden ball

we know that momentum is defined as

P=Mv

and we know also that mass of iron ball is greater than mass of wooden ball and they reached on ground at same time  and same distance it mean also velocity will be same for both ball. therefore from above relation we have

Miron*V > Mwood*V i.e.

momentum of iron ball is greater than wooden ball

5 0
3 years ago
You are in your car driving on a highway at 23 m/s when you glance in the passenger-side mirror (a convex mirror with radius of
Irina-Kira [14]

Answer:

v = 26. 88 m/s +23 m/s

Explanation:

u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m

\frac{1}{s} +\frac{1}{s'} = \frac{2}{R}

\frac{1}{2.0 m} +\frac{1}{s'} = \frac{2}{1.50 m}

Solve s'

\frac{1}{s'}  = \frac{2}{1.50 m} - \frac{1}{2.0 m}

\frac{1}{s'} =  1.833 m

s' = - 0.545 m

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\frac{ds}{dt}= \frac{s^2* \frac{ds}{dt}}{s' ^2} =\frac{2.0 ^2m * 2.0 m/s}{0.545^2m}

\frac{ds}{dt} = 26.88 m/s

Now to determine the velocity highway is going to be

v = ds/dt + u

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8 0
3 years ago
An airplane during departure has a constant acceleration of 3 m / s².
Rama09 [41]

Constant acceleration of plane = 3m/s²

a) Speed of the plane after 4s

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3m/s² = speed/4s

S = 12m/s

The speed of the plane after 4s is 12m/s.

b) Flight point will be termed as the point the plane got initial speed, u, 20m/s

Find speed after 8s, v

a = 3m/s²

from,

a = <u>v</u><u> </u><u>-</u><u> </u><u>u</u>

t

3 = <u>v</u><u> </u><u>-</u><u> </u><u>2</u><u>0</u>

8

24 = v - 20

v = 44m/s

After 8s the plane would've 44m/s speed.

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3 years ago
Two cars with the same velocity must have the same speed. True or false ?
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This is True, cars with the same velocity must have the exact same speed.
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3 years ago
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C is the best answer 
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3 years ago
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