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4 years ago

Please help...

Physics

2 answers:

zhuklara [117]4 years ago

5 0

Answer:

Option A. Emotions affect your memory as memories with strong emotional attachments are easier to recall than other memories.

Explanation:

A memory is the faculty by which the mind stores and remembers information and experiences. Psychologists believe that emotions play a determining role in whether we can recall or not a memory or a past experience at the time we try to revisit it. It is always easier to recall a memory that has an emotional aspect to it within ourselves, rather than one that does not. That is why when recalling a memory we often experience the same emotion we felt when living that moment, because emotionally charged situations can lead us to create a longer lasting memories.

kolbaska11 [484]4 years ago

3 0

I would say memories with strong emotional attachments are easier to recall than other memories.. Hope that helps !

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To accurately measure 25 mL of water, which is the best volumetric glassware to use?

Aloiza [94]

Answer:

A 25.00 mL volumetric flask

Explanation:

Normally, volumetric flasks have accuracy level of up to 0.01 L and this is more than that of other glassware provided in the choices (comment section). It’s also known that the most accurate volumetric equipment in laboratory is a volumetric flask. Therefore, to accurately measure 25 ml of a liquid, it's recommended that we use a 25.00 mL volumetric flask to accurately determine the quantity of water.

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4 years ago

BRAINLIEST!!!PLEASE HELP

olasank [31]

I believe its A
\

By inductive and deductive reseachhhhh

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4 years ago

xercise 15.29: At a distance of 6.00×1012 m from a star, the intensity of the radiation from the star is 14.7 W/m2. Assuming tha

Fynjy0 [20]

Answer:

$6.65*10^{27}W$

Explanation:

The relationship of intensity:

$I=\frac{P}{4\pi r^{2} }$

Intensity: $I=14W/m^{2}$

radius: $r=6.00*10^{12} m$

Power is unknown

Now we can apply the formula

$I=\frac{P}{4\pi r^{2} }\\P=I(4\pi r^{2})\\P=14.7(4*\pi *(6.00*10^{12} )^{2} )\\P=6.65*10^{27} W$

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3 years ago

A 4 kg and 6 kg bowling ball are dropped from the same height at the same time. The two balls strike the ground at the same time

likoan [24]

It's actually B - The 6 kg ball has a greater force of gravity exerted on them

7 0

3 years ago

Read 2 more answers

A 40-turn coil has a diameter of 11 cm. The coil is placed in a spatially uniform magnetic field of magnitude 0.40 T so that the

seropon [69]

Answer:

(a) emf = 0.507 V

(b) emf = 0.0507 V

Explanation:

Given;

number of turns of the coil, N = 40 turns

diameter of the coil, d = 11 cm

radius of the coil, r = 5.5 cm = 0.055 m

magnitude of the magnetic field, B = 0.4 T

The magnitude of the induced emf is calculated as;

$emf = - N\frac{d\phi}{dt} \\\\where;\\\\\phi \ is \ magnetic \ flux= BA \\\\A \ is the \ area \ of \ the \ coil = \pi r^2 = \pi (0.055)^2 = 0.0095 \ m^2\\\\emf = - N \frac{dB.A}{dt} = -NA\frac{dB}{dt} \\\\emf = -NA\frac{(B_2 - B_1)}{t} \\\\emf = NA \frac{(B_1 - B_2)}{t} \\\\the \ final \ magnetic \ field \ is \ reduced \ to \ zero;\ B_2 = 0\\\\emf = \frac{NAB_1}{t}$

(a) when the time, t = 0.3 s

$emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{0.3} = 0.507 \ V$

(b) when the time, t = 3.0 s

$emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{3} = 0.0507 \ V$

$emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{65} = 0.00234 \ V$

7 0

3 years ago