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3 years ago

What do these two changes have in common?

Chemistry

1 answer:

xz_007 [3.2K]3 years ago

5 0

Answer:

Both are only physical changes.

Actually, sewing an apron and dust settling out of air are both physical changes, as an apron could be unseweed by cutting the thread used, and when we disturb the dust particles, the dust particles will fet mixed back in the air so both are physical changes.

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a 160 milligram sample of a radioactive isotope decays to 10 kilograms in 12 years. what is the half life of this element

Shkiper50 [21]

Answer:

3 years

Explanation:

Given data:

Initial amount of sample = 160 Kg

Amount left after 12 years = 10 Kg

Half life = ?

Solution:

at time zero = 160 Kg

1st half life = 160/2 = 80 kg

2nd half life = 80/2 = 40 kg

3rd half life = 40 / 2 = 20 kg

4th half life = 20 / 2 = 10 kg

Half life:

HL = elapsed time / half life

12 years / 4 = 3 years

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3 years ago

2, classify the following molecules as polar or non polar.

Vitek1552 [10]

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3 years ago

A compound in a copper ore has the following percentage composition by mass:

AveGali [126]

1) since we are given percentages, we can assume we have 100 grams of the molecule.

55.6 % Cu ----> 55.6 grams Cu
16.4 % Fe------> 16.4 grams Fe
28.0% S--------> 28.0 grams S

2) convert each gram to moles using the molar masses given

$55.6 g Cu \frac{1 mol}{63.5 g} = 0.876 mol Cu$
$16.4 g Fe \frac{1 mol}{56.0 g} = 0.293 mol Fe$
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3) we divide the smallest value of moles (0.293) to each one.

Cu --> 0.876 / 0.293= 3
Fe---> 0.293 / 0.293= 1
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4) let's write the empirical formula

Cu₃FeS₃

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3 years ago