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Ivan
2 years ago
14

Select the answer for this number showing three significant figures. Remember to round if necessary. 0.566 m 0.600 m 0.570 m 0.5

00 m 0.566 m
*for science ​
Chemistry
1 answer:
sergeinik [125]2 years ago
5 0

The significant figure for 0.566 is option(d) i.e, 0.566 m.

In positional notation, significant figures are the digits in a number that is trustworthy and required to denote the amount of something. The correctness and precision of numbers are the focus of significant figures, also known as significant digits, which are crucial components of scientific and mathematical calculations. Significant numbers play a crucial role when estimating the degree of uncertainty in the outcome.

The digit following the second significant figure is known as the third significant figure of a number. It follows that this is accurate even if the digit is zero. Therefore, the third and fourth significant values of 20,499 are 4, and the third and fourth significant figures of 0.0020499 are 9, respectively.

In order for 566 to have three significant figures, we must round it

  • option 1: There is only one Significant figure, which is 0.600.
  • option2: 0.570 = Two  Significant figure.
  • option 3:  0.500 = 1 Significant Figures.
  • option4:  3 Significant Figures in 0.566

Option 4, which is equal to 0.566, is the most appropriate of the given options because it has three significant figures when it is rounded off.

To know more about significant figures refer to:  brainly.com/question/14804345

#SPJ9

.

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netineya [11]
Yes it is available. It will continue catalyzing the reactions until it becomes completely consumed. That's how enzymes work. They work and are eventually consumed in the process completely without altering the reaction in any way other than speeding it up.
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7 0
3 years ago
What does this do to the electrons outside the nucleus in the gaseous atoms
AleksandrR [38]

Answer:

Explanation:

As you know, ionization energy is the energy needed to remove one mole of electrons from one mole of atoms in the gaseous state

X

+

energy

→

X

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e

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Right from the start, you can tell that the harder it is to remove an electron from an atom, the higher the ionization energy will be.

Now, the periodic trends for ionization energy can be describe as follows

ionization energy increases as you move from left to right across a period

ionization energy decreases as you go down a group

As you mentioned, if you compare the first ionization energies for oxygen and chlorine using these two trends, you will get conflicting results.

If you follow the way ionization energy increases across period, chlorine would have a higher ionization energy, since it's closer to the noble gases.

On the other hand, if you go by how ionziation energy decreases from top to bottom in a group, oxygen would have higher ionization energy, since it's located in period 2, as compared with period 3 for chlorine.

As it turns out, the trend for groups overpowers the trend for periods. As aresult, oxygen will have a higher ionization energy than chlorine.

This happens because the smaller oxygen atom has its outermost electrons held tighter by the nucleus. By comparison, chlorine's outermost atoms are located further away from the nucleus.

Not only that, but they are screened from the charge of the nucleus better, since they're located on the third energy level.

Oxygen's outermost electrons are screened by

2

electrons, while chlorine's are screened by

8

electrons.

All these factors will make chlorine's outermost electrons a little easier to remove, which implies a smaller ionization energy than that of oxygen.v

6 0
3 years ago
When an aqueous solution containing hydrochloric acid is just neutralized with an aqueous solution containing sodium hydroxide,
Elza [17]

Answer:

c. salty.

Explanation:

From the question,

The reaction of an acid , i.e hydrochloric acid and a base i.e. , sodium hydroxide takes place , which is a type of neutralization reaction,

Where the acid and a base reacts to give salt along with water .

From the question,

The reaction is as follows -

2 HCl  +  NaOH  →  NaCl  +  H₂O  

Hence, the resulting product is a salt ,

Therefore , the resulting solution would taste like salt.

3 0
3 years ago
What volume of 0.500 M HNO3(aq) must completely react to neutralize 100.0 milliliters of 0.100 M KOH(aq)?
asambeis [7]
KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol HNO3= 1 mol KOH (keep in mind this because it will be used later).

We also know that 0.100 M KOH aqueous solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the definition of molarity).

First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/ 1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.

Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.

The final answer is </span>(2) 20.0 mL.<span>

Also, this problem can also be done by using dimensional analysis. 

Hope this would help~ </span>
6 0
3 years ago
The kb of hypochlorous acid is 3. 0×10^–8 at 26. 0 C. What is the percent of ionization of hypochlorous?
astraxan [27]

The acid dissociation constant (Ka) defines the difference between a weak and a strong acid. The % ionization of hypochlorous acid is 0.14%.

<h3>What is the acid dissociation constant?</h3>

The acid dissociation constant is used to define the ionization constant of an acidic substance. It gives the quantitative measurement of the strength.

The ICE table is attached to the image below.

The acid dissociation constant (Ka) for the reaction is,

Ka = [H⁺][ClO⁻] ÷ [HClO]

= a² ÷ (0.015 - a)

= 3.0 x 10⁻⁸

Now, a² + 3.0 x 10⁻⁸ a - 4.5 × 10⁻¹⁰ = 0

So, a = 2.210 × 10⁻⁵

Solving further,

[H+] = a = 2.210 × 10⁻⁵ M

The percent ionization is calculated as,

[H+] ÷ [HClO] × 100

= 2.210 × 10⁻⁵ M ÷ 0.015 × 100

= 0.14 %

Therefore, 0.14 % is the percentage of hypochlorous ionization.

Learn more about acid dissociation constant here:

brainly.com/question/22668939

#SPJ4

Your question is incomplete, but most probably your full question was, The ka of hypochlorous acid (HClO) is 3.0 x 10⁻⁸ at 25.0°C. What is the % of ionization of hypochlorous acid in a 0.015 aqueous solution of HClO at 25.0C?

6 0
1 year ago
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