49 grams of sulfuric acid, H2SO4, is dissolved in 1 liter of solution. Determine the molarity (M).
1 answer:
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Answer:
0.49 mol
Explanation:
Step 1: Write the balanced equation
Mg + 2 HCI ⇒ MgCl₂ + H₂
Step 2: Calculate the moles corresponding to 12 g of Mg
The molar mass of Mg is 24.31 g/mol.
Step 3: Calculate the moles of H₂ produced by 0.49 moles of Mg
The molar ratio of Mg to H₂ is 1:1. The moles of H₂ produced are 1/1 × 0.49 mol = 0.49 mol.
Answer: (a) There are 0.428 moles present in 12 g of molecule.
(b) There are 2 moles present in particles of oxygen.
Explanation:
(a). The mass of nitrogen molecule is given as 12 g.
As the molar mass of is 28 g/mol so its number of moles are calculated as follows.
So, there are 0.428 moles present in 12 g of molecule.
(b). According to the mole concept, 1 mole of every substance contains atoms.
Therefore, moles present in particles are calculated as follows.
So, there are 2 moles present in particles of oxygen.