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3 years ago

plate tectonics is a widely accepted theory due to the amount of evidence for it. list four pieces of evidence. plz help!!!!!

1 answer:

4 0

I know that the east side of South America fits into the west side of Africa almost perfectly, but not sure if that counts as evidence.

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Calculate the pressure of 2.50 Liters of a gas at 25.0oC if it has a volume of 4.50 Liters at

MariettaO [177]

Answer:

P_2 =0.51 atm

Explanation:

Given that:

Volume (V1) = 2.50 L

Temperature (T1) = 298 K

Volume (V2) = 4.50 L

at standard temperature and pressure;

Pressure (P1) = 1 atm

Temperature (T2) = 273 K

Pressure P2 = ??

Using combined gas law:

$\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2} \\ \\ \dfrac{1 *2.5}{298} = \dfrac{P_2*4.5}{273}$

$0.008389261745 \times 273 = 4.5P_2$

$P_2 =\dfrac{0.008389261745 \times 273 }{4.5}$

$P_2 =0.51 \ atm$

4 0

2 years ago

4. Chlorine exists in two forms - chlorine-35 and

White raven [17]

Answer: sorry i dont knowExplanation:

5 0

3 years ago

Consider a galvanic cell consisting of the following two redox couplesAlB+ 3e Al , Mga + 2e Mg, (ag. E® = 1.676 V ) E° = 2.356 V

malfutka [58]

Answer:

0.68 V

Explanation:

For anode;

3Mg(s) ---->3Mg^2+(aq) + 6e

For cathode;

2Al^3+(aq) + 6e -----> 2Al(s)

Overall balanced reaction equation;

3Mg(s) + 2Al^3+(aq) ----> 3Mg^2+(aq) + 2Al(s)

Since

E°anode = -2.356 V

E°cathode = -1.676 V

E°cell=-1.676 -(-2.356)

E°cell= 0.68 V

4 0

3 years ago

Look at the image below. What is the ratio of the formula shown? *

aleksklad [387]

It’s 1:1 b3cuae that’s the one u can

6 0

3 years ago

Read 2 more answers

Your boss tells you that water at 68 F is flowing in a cooling tower loop at a rate of 600 gpm, in an 8-inch inside diameter pip

avanturin [10]

Explanation:

The volumetric flow rate of water will be as follows.

q = $600 gpm \times \frac{0.000063 m^{3} s^{-1}}{1 gpm}$

= 0.0378 $m^{3}/s
$

Diameter = $8 in \times \frac{0.0254 m}{1 in}$

= 0.2032 m

Relation between area and diameter is as follows.

A = $\frac{\pi}{4} \times D^{2}$

= $\frac{3.14}{4} \times (0.2032 m)^{2}$

= 0.785 x 0.2032 x 0.2032

= 0.0324 $m^{2}$

Also, q = A × V

or, V = $\frac{q}{A}$

= $\frac{0.0378 m^{3}/s}{0.0324 m^{2}}$

= 1.166 m/s

As, viscosity of water = 1 cP = $10^{-3}$ Pa-s

Density of water = 1000 $kg/m^{3}$

Therefore, we will calculate Reynolds number as follows.

Reynolds number = $\frac{D \times V \times density}{viscosity}$

= $\frac{0.2032 m \times 1.166 m/s \times 1000}{10^{-3}}$

= 236931.2

Hence, the flow will be turbulent in nature.

Thus, we can conclude that the Reynolds number is 236931.2 and flow is turbulent.

8 0

3 years ago