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nirvana33 [79]
3 years ago
11

Which is more dense lead or Gold ?

Physics
2 answers:
WARRIOR [948]3 years ago
8 0

Answer:

Gold is more dense.

Gold sinks faster than lead. That's why gold is found in the bottom of a gold pan or river.

never [62]3 years ago
4 0

Answer:

Gold is much heavier than lead. It is very dense. ... Therefore gold weighs 19.3 times as much or (19.3 x 8.3 lb) about 160 pounds per gallon. Although gold has a density 19.3 times greater than water and is one of the most dense substances on Earth, there are substances with far more amazing densities.

Explanation:

please mark me brainliest

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A pulley has a mechanical advantage of 1.
sertanlavr [38]

Answer:

There is no mechanical advantage

Explanation:

The mechanical advantage is possible only when the force needed to lift a load is lesser than the weight of the load.

For example, is we have a mechanical advantage of 2, the force needed to lift will be 1/2 of the weight of the load, and if we have a mechanical advantage of 4, the force needed will be 1/4 of the weight of the load.

In the attached image there are clear examples of mechanical advantage with pulleys.

7 0
3 years ago
A student pulls a 50-newton sled with a force having a magnitude of 15 newtons. What is the magnitude of the force that the sled
Simora [160]

Answer:

Force = 35 N

Explanation:

From Newton's third law of motion, the boy must apply a force greater than the weight of the sled to lift it.

weight of sled = mg

where m is its mass and g the force of gravity on it.

weight of sled = 50 N

Force applied by the boy on the sled = 15 N

Since the force applied on the sled by the boy is lesser than the weight of the sled, then;

Force that the sled exerts on the student = 50 - 15

                                             = 35 N

The force exerted by the sled on the student is 35 N.

5 0
3 years ago
For a charged particle, a constant magnetic field can be used to change
Leona [35]
The direction of motion of the charge
5 0
3 years ago
Which statement best describes a primary source?
Fantom [35]

Answer:

I go with D but what you can do is u can read each and choose the one that sounds right Hope this helps

3 0
3 years ago
In an experiment conducted using the Young's double-slit apparatus, the separation between the slits is 20 µm. A first-order con
jeka57 [31]
To solve this problem, we use the formula
λ = s sin θ
where s is the separation and θ is the angle interference
So,
λ = 20 x 10^-6 sin 2.5
λ = 8.72 x 10^-7 m

The required angle for the fourth order bright fringe is
θb = sin⁻¹ (4λ / s) = sin⁻¹ (4 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 10.04°

The required angle for the fourth order dark fringe is
θd = sin⁻¹ (4.5 λ / s) = sin⁻¹ (4.5 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 11.31°
6 0
3 years ago
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