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padilas [110]
2 years ago
10

Problem 6. A negatively charged particle is placed in a uniform electric field directed

Physics
1 answer:
Montano1993 [528]2 years ago
8 0

<u>C</u><u>)</u><u> </u><u>South</u>

As we know that, north is considered as negative, and south as positive. Now, the charge on particle is negative; so, when we will release it, it will move towards the south.

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If a student is sitting in their chair and the leg of the chair breaks the student will __________ toward the floor because the
USPshnik [31]

Answer:

theyll accelerate towards the floor :)

5 0
3 years ago
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A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 500 V . The rat
max2010maxim [7]

Answer:

Explanation:

 Rate of dissipation of energy at resistor

= I² R = 296

current I² = 296/R = 296 / 300

I = 0.9933 A.

Impedence Z = V / I = 500 / .9933

= 503 ohm.

B ) Let it be V

voltage across resistance = 300 x .9933 = 298 v

Now 500² = 298² + V²

V = 401 v

C)  Power factor = R / Z

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6 0
3 years ago
I don’t get question number 10 for science
jeyben [28]

a. matter

b. mass

c. weight

d. gravity does not change

e. determined by gravity

f. location determines amount

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Weight is determined by gravity because you would way less on the moon that doesn't have that much of a gravitational pull. That's why people jump really high on the moon. that's also why the location determines the amount.

Mass however doesn't change by gravity. When you go to the moon you do not loose more of yourself or become smaller, you stay the same size. That is part of mass.

5 0
3 years ago
Which of the following does not accurately transistors
seropon [69]

Both NPN and PNP transistors consist of a base composed of an N-type material.

4 0
3 years ago
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A very long wire carries a uniform linear charge density of 5 nC/m. What is the electric field strength 13 m from the center of
kipiarov [429]

Answer:

E=6.91 N/C

Explanation:

Given that

Linear Charge density ,λ = 5 nC/m

Distance ,R= 13 m

We know that formula for long wire to find electric field

E=\dfrac{\lambda }{2\pi \varepsilon _0R}

E=Electric field

R=Distance

εo=8.85 x 10⁻¹² C²/N.m²

λ=Linear Charge density

Now by putting the values

E=\dfrac{5\times 10^{-9}}{{2\times \pi \times 8.85\times 10^{-12}\times 13}}

E=6.91 N/C

Therefore the electric filed at distance 13 m will be 6.91 N/C

5 0
3 years ago
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