In scientific notation, if the exponent of 10 is positive, the number is very very large. In the metric system, very large numbers are expressed in megameters (Mm) or gigameters (Gm). Gigameters is equal to 10⁹ meters. So, in SI prefix, that would be equal to 150 Gm. In kilometers, that would be equal to:
1.5×10¹¹ m * (1 km/1000 m) = 1.5×10⁸ km
<span>First let's find the acceleration required in the barrel to speed the ball up from 0 to 83 m/s in a distance of 2.17 m. We know the force the cannon exerts on the cannonball is 20000 N; if we can find this acceleration then we can use F = ma to find the mass.
We can find the acceleration using one of the kinematic equations of motion. We have:
u = initial speed = 0 m/s
v = final speed = v0 = 83 m/s
d = distance = 2.17 m
a = acceleration = ?
v² = u² + 2ad. Since u = 0, this reduces to v² = 2ad and rearranges to a = v²/2d = 83²/2*2.17 = 83²/4.34 = 1587.327 m/s².
Now F = ma, so m = F/a = (20000N)/(1587.327 m/s²) = 12.6 kg.
For part 2, use the Range Equation:
If R is the horizontal distance the cannonball travels,
v = v0 = the initial velocity = 83 m/s
g = acceleration due to gravity - 9.8 m/s²
x the launch angle relative to the horizontal, then
R = (v²sin(2x))/g.
So R = (83²sin(2*37))/9.8
= (6889sin74)/9.8 = 676 m.
So the target ship is 676 m away.</span>
You would have to subtract the mass number with atomic number which will give you 119 number of neutrons.
Centripetal force of satellite = gravitational force between earth and the satellite
(m•v^2)/r = (G•Me•m)/r^2
v^2 = (G•Me)/r
v^2 = 6.67x10^-11 x 5.598x10^24 / 7.5x10^7
v = 2231 m/s
so answer is B
Answer:
Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.