



<u>According to given question</u> :

<span>A) x = 41t
The classic equation for distance is velocity multiplied by time. And unfortunately, all of your available options have the form of that equation. In fact, the only difference between any of the equations is what looks to be velocity. And in order to solve the problem initially, you need to divide the velocity vector into a vertical velocity vector and a horizontal velocity vector. And the horizontal velocity vector is simply the cosine of the angle multiplied by the total velocity. So
H = 120*cos(70) = 120*0.34202 = 41.04242
So the horizontal velocity is about 41 m/s. Looking at the available options, only "A" even comes close.</span>
Answer:

Explanation:
Given:
cross sectional area of the bone, 
factor of up-scaling the dimensions, 
Since we need to find the upscaled area having two degrees of the dimension therefore the scaling factor gets squared for the area being it in 2-dimensions.
The scaled up area is:

![a_s=[4.8 \times 10^{-4}]\times 10^2](https://tex.z-dn.net/?f=a_s%3D%5B4.8%20%5Ctimes%2010%5E%7B-4%7D%5D%5Ctimes%2010%5E2)

Answer:
Can two like charges attract each other : True ( Yes)
We are asked in the problem to determine the <span>distance of an electron in which the electric field strength is equal to e/3. we use the gravitational formula of E = m1m2/d^2
hence,
e = m1m2/1 = k/1 =k
e/2 = k/d^2
e/2=e/d^2
d^2 = 2
d = sqrt 2 = </span><span>1.41 cm</span>