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Mashutka [201]
3 years ago
11

The type of synapse that occurs between the terminal end of the presynaptic cell and the perikaryon of the postsynaptic cell is

referred to as which kind of synapse?
Physics
1 answer:
ASHA 777 [7]3 years ago
5 0

Answer:

axosomatic synapse

Explanation:

Axosomatic synapse -

It refer to the junction between the nerves cells , is referred to as axosomatic synapse .

The junction between the axon of one neuron and the body of the other neuron is where the axosomatic synapse resides .

Via this junction the message in the form of certain chemicals or impulse gets transmitted , from one point of the by to other .

Hence , from the given information of the question ,

The correct term is axosomatic synapse .

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What is the net force (including direction and magnitude) acting on the object on the above left?
Ber [7]

Answer:

Explanation:

the net force on the right left is 25 N and is directed upward

the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero

i hope this will help you

7 0
2 years ago
A box of unknown mass is sliding with an initial speed vi = 5.60 m/s across a horizontal frictionless warehouse floor when it en
Maksim231197 [3]

We know that the Delta E + W(Work done by non-conservative forces) = 0 (change of energy)

In here, the non-conservative force is the friction force where f = uN (u =kinetic friction coefficient) 

W= f x d = uNd ; N=mg 
Delta E = 1/2 mV^2 -1/2mVi^2 

umgd + 1/2mV^2 - 1/2mVi^2 = 0 (cancel out the m term) 

This will then give us: 

1/2Vi^2-ugd = 1/2V^2 

V^2 = Vi^2 - 2ugd

So plugging in our values, will give us:

V= Sqrt (5.6^2 -2.3^2)

=sqrt (26.07)

= 5.11 m/s 

 

6 0
3 years ago
Sawyer launches his 180 kg raft on the Mississippi River by pushing on it with a force of 75N. How long must Sawyer push on the
Daniel [21]

Answer: 4.8 s

Explanation:

We have the following data:

m=180 kg the mass of the raft

F=75 N the force applied by Sawyer

V=2 m/s the raft's final speed

V_{o}=0 m/s the raft's initial speed (assuming it starts from rest)

We have to find the time t

Well, according to Newton's second law of motion we have:

F=m.a (1)

Where a is the acceleration, which can be expressed as:

a=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{t-t_{o}} (2)

Substituting (2) in (1):

F=m\frac{V-V_{o}}{t-t_{o}} (3)

Where t_{o}=0

Isolating t from (3):

t=\frac{m(V-V_{o})}{F} (4)

t=\frac{180 kg(2 m/s-0 m/s)}{75 N}

Finally:

t=4.8 s

6 0
3 years ago
a student pushes a box with a total mass of 50kg. what is the net force on the box if it accelerates 1.5 m/s^2?
Zielflug [23.3K]
F=mass times acceleration so multiple 50 by 1.5 and u get 75

5 0
3 years ago
A hiker is at the bottom of a canyon facing the canyon wall closest to her. She is 790.5 meters from the wall and the sound of h
tester [92]

Answer:

4.80 seconds

Explanation:

The velocity of sound is obtained from;

V= 2d/t

Where;

V= velocity of sound = 329.2 ms-1

d= distance from the wall = 790.5 m

t= time = the unknown

t= 2d/V

t= 2 × 790.5/ 329.2

t= 4.80 seconds

7 0
3 years ago
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