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Mashutka [201]
3 years ago
11

The type of synapse that occurs between the terminal end of the presynaptic cell and the perikaryon of the postsynaptic cell is

referred to as which kind of synapse?
Physics
1 answer:
ASHA 777 [7]3 years ago
5 0

Answer:

axosomatic synapse

Explanation:

Axosomatic synapse -

It refer to the junction between the nerves cells , is referred to as axosomatic synapse .

The junction between the axon of one neuron and the body of the other neuron is where the axosomatic synapse resides .

Via this junction the message in the form of certain chemicals or impulse gets transmitted , from one point of the by to other .

Hence , from the given information of the question ,

The correct term is axosomatic synapse .

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An airplane capable of an airspeed of 100 km/hr is 60 km off the coast above the sea. If the wind is blowing from the coast out
Nady [450]

To solve this problem we will apply the concepts related to relative speed. We will obtain it from the deduction made on the aircraft as a speed of the two components that act on it. Through the kinematic equations of motion, we can then calculate the time required.

The airspeed of airplane is 100km/h  while the wind is blowing from the coast out to sea at 40km/h. Wind is blowing from the coast out to sea means that it opposes the airspeed. Therefore, resultant relative speed of airplane is

v_r = 100-40=60km/h

Total distance is 60km then with this net velocity we have that the required time is

v = \frac{x}{t} \rightarrow t = \frac{x}{v}

Where,

x = Displacement

t = Time

v = Velocity

Replacing,

t = \frac{60km}{60km/h} = 1hour

t = 60 minutes

Therefore the time taken by the plane to reach the shore is 60 minutes

6 0
3 years ago
If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed? (1 point)
ludmilkaskok [199]

If electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.

<h3>Bahavior of particles in double-slit experiment</h3>

In a double-slit experiment, single particles, such as photons, pass one at a time through a screen containing two slits.

The photons behave like wave and the constructive interfernce of the waves of these photons will generate a high amplitude wave seen as a bright band in the center of the screen.

Thus, if electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.

Learn more about double slit experiment here: brainly.com/question/4449144

6 0
2 years ago
A man starts walking from home and walks 2 miles at 20° north of west, then 4 miles at 10° west of south, then 3 miles at 15° no
Rzqust [24]

Answer:

a)  R = 2.5 mi   b)  To return to your case you must walk in the opposite direction or θ = 98º

This is 8º north west

Explanation:

This is a distance exercise with vectors the best way to work these is to decompose the vectors and perform the sum on each axis separately

To use the Cartesian system all angles must be measured from the positive side of the x-axis or the signs of the components must be assigned manually depending on the quadrant where they are.

First vector A = 2 to 20º north west

Measured from the positive x axis is θ = 180 -20 = 160º

We use trigonometry to find the components

     Cos 20 = Aₓ / A

     sin 20 = A_{y} / A

    Aₓ = A cos 160 = 2 cos 160

    A_{y}  = A sin160 = 2 sin160

    Aₓ = -1,879 mi

    A_{y}  = 0.684 mi

Second vector B = 4 mi 10º west of the south

Angle θ = 270 - 10 = 260º

    cos 2600 = Bₓ / B

    sin 260 = B_{y} / B

    Bₓ = B cos 260

     B_{y}  = B sin 260

    Bₓ = 4 cos 260

     B_{y}  = 4 sin 260

     Bₓ = -0.6946mi

     B_{y}  = - 3,939 mi

Third vector C = 3 mi to 15 north east

     cos 15 = Cₓ / C

     sin15 = C_{y} / C

     Cₓ = C cos 15

     C_{y} = C sin15

     Cₓ = 3 cos 15

    C_{y} = 3 sin 15

     Cₓ = 2,898 mi

    C_{y} = 0.7765 mi

Now we can find the final position of the person

    X = Aₓ + Bₓ + Cₓ

    X = -1.879 -0.6949 + 2.898

    X = 0.3241 mi

    Y = A_{y} +  B_{y} + C_{y}

    Y = 0.684 - 3.939 +0.7765

    Y = -2.4785 mi

a) We use Pythagoras' theorem

     R = √ (x2 + y2)

     R = √ (0.3241 2 + (-2.4785) 2)

     R = 2.4996 mi

     R = 2.5 mi

b) let's use trigonometry

     Tan θ = y / x

     Tanθ  = -2.4785 / 0.3241

     θ = tan⁻¹ (-7,647)

     θ = -82

Measured from the positive side of the x axis is Te = 360 - 82 = 278º

(90-82) south east

To return to your case you must walk in the opposite direction or Te = 98º

This is 8º north west

3 0
3 years ago
1) La longitud del brazo de potencia de una palanca es de 0,0035 hectómetros y la del brazo de resistencia es de 55 centímetros.
Arlecino [84]

Answer:

Entonces seria 127 para vencer.

Explanation:

espero averte ayudado:-)

6 0
3 years ago
On vacation at the beach, you bring a radio to the beach. The radio can pick up several different radio stations.Which is the be
Harrizon [31]

D) waves are used to transmit the rail signal though the air. these waves are encoded at different frequencies for different stations

7 0
3 years ago
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