The outer rigid layer of the earth is divided into a couple of dozen “plates” that move around across earths surface relative to each other.
Answer:
60
Explanation:
According to the given question, the computation of minimum coating thickness is shown below:-
The condition for constructive interference is
![2t_{min} = (m + \frac{1}{2} )\times \frac{\lambda}{^nmateral}](https://tex.z-dn.net/?f=2t_%7Bmin%7D%20%3D%20%28m%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%29%5Ctimes%20%5Cfrac%7B%5Clambda%7D%7B%5Enmateral%7D)
![= (0 + \frac{1}{2} )\times \frac{\lambda}{^nmateral}](https://tex.z-dn.net/?f=%3D%20%280%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%29%5Ctimes%20%5Cfrac%7B%5Clambda%7D%7B%5Enmateral%7D)
![t = \frac{\lambda}{4n}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Clambda%7D%7B4n%7D)
Now we will put the values to the above formula to reach the answer
![= \frac{480nm}{4\times 2.0}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B480nm%7D%7B4%5Ctimes%202.0%7D)
= 60
Therefore we simply applied the above formula to determine the minimum coating thickness
147.09975 newton meters per second
Answer:
by shift do you mean travel
Explanation: