Write the factors of potential energy

In a Little League baseball game, the 145 g ball reaches the batter with a speed of 15.0 m/s. The batter hits the ball, and it l

Oduvanchick [21]

Answer: 5.075Ns

Explanation:

Given the following :

Mass of ball = 145g

Initial Speed of ball = 15m/s

Final speed of ball when hit by the batter = - 20m/s ( Opposite direction)

The impulse of a body is represented using the relation:

Force(f) * time(t) = mass (m) * (final Velocity(V) - initial velocity(u))

Therefore, using:

m(v - u) = impulse

Mass of ball = 145 / 1000 = 0.145kg

Impulse = 0.145(- 20 - 15)

Impulse = 0.145(-35)

Impulse = 5.075Ns

3 0

2 years ago

What property do the following elements have in common? sulfur, iodine, and magnesium A) Same phase at room temperature. B) Good

kolbaska11 [484]

Sulphur (S), Iodine (I) and Magnesium (Mg) are all three, solids at the room temperature. Thus they have the same phase at room temperature.
Sulphur and Iodine are not good conductors of electricity.
Also while Sulphur is in group 6, Magnesium is in group 2. Therefore they do not have the same number of valence electrons. Sulphur is making anions (negative ions) and Magnesium is making cations (positive ions).

7 0

3 years ago

Read 2 more answers

Why are certain metalloids useful in today's technological equipment?

fgiga [73]

The answer is B.

Metalloids are elements that posses some of the characteristics of non-metals and also some of the characteristics of metals.

The semiconductivity property of metalloids such as Siliconium, Geranium have been leveraged to the maximum and these are used in LCD screens, televisions and many other technological appliances.

8 0

2 years ago

How is kinetic energy related to the distance

astra-53 [7]

Kinetic energy =

1/2 (mass) • (velocity squared).

I don't see distance in that formula anywhere, so they're not related.

8 0

3 years ago

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One block rests upon a horizontal surface. A second identical block rests upon the first one. The coefficient of static friction

goblinko [34]

Answer:

The magnitud of the force is 124.8N.

Explanation:

First we have to find the value of the static friction coefficient, when the external force F is applied to upper block (i will call it A Block) we have a free body diagram as the one shown in the figure i attached, so since this block has no aceleration in any direction the force F should be equal to the friction force between A and B block, one we noticed this we can use the equation for the Friction force to find the coefficient:

$0=F-FrictionAB$

$F=FrictionAB=Nab*$ μs

and again, since the block has no acceleration the normal between A and B block should be equal to the weigth of the first block, so we have:

$0=Nab-W$

$Nab=W=mg$

replacing this we have:

$F=$ μs $*Nab=$ μs* $mg=41.6N$

and μs $=41.6N/(mg)$

now it's time to see the free body diagram for the b block, if we now apply the F force to the B block the diagram should look like in the figure.

the color of the arrow gives you an idea of where the force comes from, the blue ones comes from the B block, the red ones from the A block and the brown ones from the ground.

now for the B block you can see two friction forces, one for the ground and one for the A block, both of these directed bacwards, and two normal forces, again one for the ground and one for the A block but the normal force for the A block is aiming downwards.

again we use the fact that the block is not accelerating in any direction so the sum of the forces in x and y direction have to be 0, so:

$F-Friction1(ground)-Friction2(AB)=0$