2Cu(NO3)2 ----------> 2CuO (s) +4NO2 (g) + O2(g)
9.378g=0.05moles
no of moles = weight / MW = 9.378/187.56 = 0.05moles
as per the above reaaction 2moles of Cu(NO3)2 can produce 4moles of N2
0.05moles Cu(NO3)2 can produce (0.05*4)/2 = 0.1moles of N2
and 2moles of Cu(NO3)2 can produce 1moles of O2
0.05moles Cu(NO3)2 can produce (0.05*1)/2 = 0.025moles of O2
Total moles of gas i.e., N2 and O2 =0.1+0.025 = 0.125moles
From PV = nRT
V = nRT/ P = 0.125*0.0821*273 = 2.80166Lit option is correct
Answer:
Option "C" is the correct answer to the following question.
Explanation:
Given:
Pressure in an automobile tire (P) = 1.88 atm
Temperature (K) = 25°C = 273 + 25 = 298 Kelvin
New temperature (K1) = 37°C = 273 + 37 = 310 Kelvin
Find:
New pressure in an automobile tire (P1) = ?
Computation:
New pressure in an automobile tire (P1) = 1.9557
New pressure in an automobile tire (P1) = 1.96 (Approx)
Thomson realized that the accepted model of an atom did not account for negatively or positively charged particles. Therefore, he proposed a model of the atom which he likened to plum pudding. ... Rutherford with the assistance of Ernest Marsden and Hans Geiger performed a series of experiments using alpha particles.
The element having valency of 1 is ~
