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2 years ago

Why does waters boiling point decrease with increases in elevation

Chemistry

2 answers:

Delvig [45]2 years ago

4 0

My friend, let's take an example

Say you have gone camping in the mountains. And that you meet a river on way up. From the river, you are going to take water because you know you will need it. So you took the water and continued the journey up. Now you have come to a high altitude. Now you are thirsty. We can't trust water so we boil it to kill germs and bacteria. You notice that the water has boiled quickly. Now the reason is that higher altitudes have low atmospheric pressure. So the boiling point decreases.

Now you might be wondering why I gave such a lengthy description. My aim is to tell the answer with some imagination so that it will get stuck in your head for a really long time so that you don't have to waste points and time.

Have a good day!

lesantik [10]2 years ago

3 0

Answer:

Waters' boiling point decreases with increases in elevation because of the atmospheric pressure.

For example, the higher in elevation you are. The lower the atmospheric pressure is. In other words heated water reached boiling point quicker.

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What is the pOH of 0.5 M KOH?

jenyasd209 [6]

Answer:

pOH = 0.3

Explanation:

As KOH is a strong base, the molar concentration of OH⁻ is equal to the molar concentration of the solution. That means that in this case:

[OH⁻] = 0.5 M

With that information in mind we can<u> calculate the pOH </u>by using the following formula:

pOH = -log[OH⁻]

pOH = -log(0.5)

pOH = 0.3

5 0

2 years ago

must undergo addition because they have easily broken π bonds. ____________ rule states in the addition of HX to an unsymmetrica

erastova [34]

Answer:

Alkenes, Markovnikov's, Alkenes, Alkyl halides, and less.

Explanation:

Alkenes must undergo addition because they have easily broken π bonds.

Markovnikov's rule states in the addition of HX to an unsymmetrical alkene, the H atom bonds to the less substituted carbon atom.

Alkenes are unsaturated hydrocarbons because they have fewer than the maximum number of hydrogen atoms per carbon.

Alkyl halides have good leaving groups and therefore readily undergo substitution and elimination reactions.

In hydroboration, the boron atom bonds to the less substituted carbon.

3 0

2 years ago

I have a balloon that can hold 125,000 mL of air. If I blow up this balloon with 3 moles of oxygen gas at a

matrenka [14]

Answer:

234.35 °C

Explanation:

Given data:

Volume of balloon = 125000 mL

Moles of oxygen = 3 mol

Pressure = 1 atm

Temperature = ?

Solution:

Formula:

PV = nRT

P = Pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

Volume of balloon = 125000 mL × 1 L /1000 mL

Volume of balloon = 125 L

Now we will put the values:

Ideal gas constant = R = 0.0821 atm.L/mol.K

PV = nRT

T = PV/nR

T = 1 atm × 125 L/ 0.0821 atm.L/mol.K × 3 mol

T= 125 /0.2463 /K

T = 507.5 K

K to °C

507.5 K - 273.15 = 234.35 °C

4 0

2 years ago

How do the chemical properties of the halegons compare to those of the noble gases

saul85 [17]

Answer:

The halogens are extremely reactive, whilst the noble gases are mainly inert.

Only some noble gases tend to form compounds, such as xenon and krypton. However, some like helium, almost have no compounds at all. Noble gases also have octet rule shells, which causes the little reactivity associated with them. To form bonds with noble gases, a lot of energy is required to form those bonds. Halogens, on the other hand, are extremely reactive. Compounds like chlorine and fluorine must be stored carefully, as they will oxidise anything that they can find, just to get one extra electron to get an octet configuration.

Hope this helps :)

6 0

2 years ago

Read 2 more answers

Hno3, a strong acid, is added to shift the ag2co3 equilibrium (equation 7.6) to the right. explain why the shift occurs.

Deffense [45]

Answer 1) When a strong acid like $HNO_{3}$ reacts with $Ag_{2} CO_{3}$ usually the equilibrium shifts to the right because

As per the Le chatelier's principle "if in any reaction, a dynamic equilibrium is disturbed by changing the any of the conditions, the position of equilibrium moves to counteract the change." So, in the given reaction when $HNO_{3}$ reacts with $Ag_{2} CO_{3}$ it generates carbon dioxide and water as a by product, if we are adding $HNO_{3}$ it will remove some of the $CO_{3}$ molecule from the reaction mixture, which then tends to shift the equilibrium towards right.

Answer 2) The same would be observed in this case, if we replace $HNO_{3}$ with HCl it will shift the equilibrium to the right as their will be generation of AgCl as the precipitate.

As per the definition of Le Chatelier's principle if we add reactants in the reaction the equilibrium will tend to move towards right, also if we replace the products or remove it then too it will shift the equilibrium towards right. So, in this reaction you are removing $Ag^{+}$ and $Cl^{-}$ ions from the solution.

7 0

2 years ago