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Rina8888 [55]
2 years ago
13

Choose the correct missing coefficient to balance the following equation:

Chemistry
1 answer:
ira [324]2 years ago
6 0

Answer:

the answer is 2 hope this helps

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An inhibitor is added to an enzyme-catalyzed reaction at a concentration of 26.7 μM. The Vmax remains constant at 50.0 μM/s, but
fomenos

Using the Michaelis-Menten equation competitive inhibition, the Inhibition constant, Ki of the inhibitor is 53.4 μM.

<h3>What is the Ki for the inhibitor?</h3>

The Ki of an inhibitor is known as the inhibition constant.

The inhibition is a competitive inhibition as the Vmax is unchanged but Km changes.

Using the Michaelis-Menten equation for inhibition:

  • Kma = Km/(1 + [I]/Ki)

Making Ki subject of the formula:

  • Ki = [I]/{(Kma/Km) - 1}

where:

  • Kma is the apparent Km due to inhibitor
  • Km is the Km of the enzyme-catalyzed reaction
  • [I] is the concentration of the inhibitor

Solving for Ki:

where

[I] = 26.7 μM

Km = 1.0

Kma = (150% × 1 ) + 1 = 2.5

Ki = 26.7 μM/{(2.5/1) - 1)

Ki = 53.4 μM

Therefore, the Inhibition constant, Ki of the inhibitor is 53.4 μM.

Learn more about enzyme inhibition at: brainly.com/question/13618533

5 0
2 years ago
5. A particular anticodon is 5'-AGC-3'. The codon that is a precise complementary base pair match for this is 5'-AGU-3'. However
Veseljchak [2.6K]

Explanation:

Wobble Hypothesis given by Francis Harry Compton Crick states that 3rd base of mRNA codon can base pair with 1st base of a tRNA anticodon undergoing non-Watson-Crick.

The first 2 bases of the mRNA codon form Hydrogen bonds with the corresponding bases on tRNA anticodon in Watson-Crick manner. Through this, they only form the base pairs with the complimentary bases. However, formation of the Hydrogen bonds between 3rd base on codon and 1st base on anticodon can occur potentially in non-Watson-Crick manner.  

<u>Thus, the Wobble Hypothesis explains that why the multiple codons can code for single amino acid.</u>

3 0
3 years ago
if a gas has an initial pressure of 24,650 pa and an initial volume of 376 ml, what is the final volume if the pressure of the g
NNADVOKAT [17]

If a gas has an initial pressure of 24,650 pa and an initial volume of 376 ml, then the final volume would be 11,943.8144 ml if the pressure of the gas is changed to 775 torr assuming that the amount and the temperature of the gas remain constant.

It is given that the initial pressure P₁ is 24,650Pa and initial volumeV₁ is 376ml and the final pressureP₂ is 775 torr. We need to find the final volume of the gas. The final volume could be found using the following formula:

P₁V₁ = P₂V₂

By substituting the values, we get

24650 x 376 = 776 x V₂

9268400 = 776V₂

V₂ = 9268400/776

V₂ = 11,943.8144 ml

Therefore, the final volume of the gas would be 11,943.8144 ml

To know more about Partial pressure, click below:

brainly.com/question/14119417

#SPJ4

5 0
10 months ago
Which type of electromagnetic wave has the greatest frequency?(1 point)
Citrus2011 [14]

c. x-rays

My answer is that x-rays or gamma rays have the greatest (or highest) frequency waves.

8 0
3 years ago
Which animal can leave its eggs to hatch and does not need to take care of the infants?
Murljashka [212]
Sea turtles they leave them on the beach
4 0
2 years ago
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