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Nata [24]
3 years ago
5

Sugar dissolved completely in water to form a solution. The solution is a ? pleasee help

Chemistry
1 answer:
aksik [14]3 years ago
4 0

Answer:

the mixture or solution is called homogeneous mixture

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Write a balanced half-reaction describing the reduction of aqueous iron(III) cations to aqueous iron(II) cations.​
melamori03 [73]

Answer:

The answer to your question is:

Explanation:

                  Iron (III)  ⇒ Iron (II)

                  Fe⁺³ + 1e⁻   ⇒   Fe⁺²

                 

6 0
4 years ago
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PLZ help me with this question
Karo-lina-s [1.5K]
Mean: 237.5
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3 years ago
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Two identical bottles at the same temperature contain the same gas. If bottle B has twice the volume and contains half the numbe
yuradex [85]

Answer:

The ratio of pressure in bottle B to that of bottle A is 1 : 4

Explanation:

We'll be by calculating the pressure in both bottles. This is illustrated below below:

For A:

Temperature (T) = T

Volume (V) = V

Number of mole (n) = n

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =...?

PV = nRT

PV = n x 0.0821 x T

Divide both side by V

P = nT0.0821/V

Therefore, the pressure, in bottle A is

PA = nT0.0821/V

For B:

Temperature (T) = the same as that of A = T

Volume (V) = twice that of A = 2V

Number of mole (n) = half that of A = ½n

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =...?

PV = nRT

P x 2V = ½n x 0.0821 x T

Divide both side by 2V

P = ½n x 0.0821 x T/2V

P = nT0.0821/4V

Therefore, the pressure in bottle B is:

PB = nT0.0821/4V

Now, we can obtain the ratio of pressure in bottle B to that of bottle A as follow:

Pressure in bottle A (PA) = nT0.0821/V

Pressure in bottle B (PB) = nT0.0821/4V

PB/PA = nT0.0821/4V ÷ nT0.0821/V

PB/PA = nT0.0821/4V x V/nT0.0821

PB/PA = 1/4

Therefore, the ratio of pressure in bottle B to that of bottle A is 1 : 4.

3 0
4 years ago
Need help with this please help ASAP
gregori [183]

Answer:

The correct answer would be -

17. 50% chances of round offspring

18. 25% chances two copies of dominant allele in the genotype of offspring

Explanation:

17. In this question it is stated that the Spongebob is heterozygous and has a square body which means the square body is dominant over the round that is present in sponge Susie that means she has two copies of the recessive allele.

S for square trait and s for a round trait then

    S     s

s Ss    ss

s Ss    ss

Thus, the correct answer is 50 percent as there are only two copies of ss.

18. in this question Patric and Patti both have heterozygous for the pink (P) body-color dominant over yellow (p). The chances for the true-breeding dominant genotype would be -

     P    p

P   PP  Pp

p   Pp  pp

There is only one out of four rue-breeding dominant offspring will be produced.

3 0
3 years ago
13. Copper(II) chloride and silver acetate Acid/Base:
Lubov Fominskaja [6]

Answer:

13. CuCl_2 \hspace{0.1cm}+ CH_3COOAg -> AgCl \hspace{0.1cm} + (CH_3COO)_2Cu

This is a double displacement reaction, not an acid-base reaction

14.HF\hspace{0.1cm}+Ba(OH)_2 ->\hspace{0.1cm}H_2O\hspace{0.1cm}+BaF_2

Ba(OH)_2 -> Base

HF -> Acid

15. HCl\hspace{0.1cm}+Mg(OH)_2->\hspace{0.1cm}H_2O\hspace{0.1cm}+MgCl_2

MgCl_2 -> Base

HCl -> Acid

16.CH_3COOH\hspace{0.1cm}+LiOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+CH_3COOLi

LiOH -> Base

CH_3COOH -> Acid

17.H_2SO_4\hspace{0.1cm}+NaOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaHSO_4

NaOH -> Base

H_2SO_4-> Acid

18. H_2SO_4\hspace{0.1cm}+NaOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaHSO_4

NaOH -> Base

H_2SO_4-> Acid

19.H_2SO_4\hspace{0.1cm}+NaHCO3->\hspace{0.1cm}H_2O\hspace{0.1cm}+CO_2+\hspace{0.1cm}Na_2SO_4

NaHCO_3-> Base

H_2SO_4-> Acid

20.H_3PO_4\hspace{0.1cm}+Zn(OH)_4->\hspace{0.1cm}H_2O\hspace{0.1cm}+Zn_3(PO_4)_4

Zn(OH)_4> Base

H_3PO_4-> Acid

21. HF\hspace{0.1cm}+Na_2SO_3->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaF\hspace{0.1cm}+\hspace{0.1cm}SO_2

NaSO_2> Base

HF-> Acid

22.HCl\hspace{0.1cm}+Na_2SO_3->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaCl\hspace{0.1cm}+\hspace{0.1cm}SO_2

NaSO_2> Base

HCl-> Acid

23.HCl\hspace{0.1cm}+Na_2S->\hspace{0.1cm}H_2S\hspace{0.1cm}+NaCl

Na_2S> Base

HCl-> Acid

24. NH_4Cl\hspace{0.1cm}+NaOH->\hspace{0.1cm}H_2O\hspace{0.1cm}+NaCl+{0.1cm}NH_3

NaOH> Base

NH_4Cl-> Acid

Explanation:

All acid-base reaction have the same products, H_2O and a salt. Whit this in mind the acids would the compounds that produces the hydronium ion (H^+) and the bases would be the compounds that produces the hydroxide ion (OH^-)

8 0
3 years ago
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