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3 years ago

Sugar dissolved completely in water to form a solution. The solution is a ? pleasee help

Chemistry

1 answer:

aksik [14]3 years ago

4 0

Answer:

the mixture or solution is called homogeneous mixture

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How many formula units are there in 212 grams of mgCl2

AleksandrR [38]

Formula units are there in 212 grams of MgCl₂ are 830.56

Formula is the empirical of any ionic or covalent network solid compound used as an independent entity for stoichiometric calculations and it is the lowest whole number ratio of ions represented in an ionic compound

Here given data is

MgCl₂ = 212 grams

1 mole of magnesium chloride has mass = 95.211 gram and contains 6.022×10²³formula units of magnesium chloride

Here 212 grams×6.022×10²³form unit of MgCl₂/95.211 gram = 830.56

Know more about magnesium chloride

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10 months ago

If you have a density of 3g/meander a mass of 15g what is the volume?

erma4kov [3.2K]

M=D*V,
V=m/D
m=15 g
D=3 g/ml
V=15 g/3 g/ml=5 ml

7 0

3 years ago

How many moles of CO2 are produced from the combustion of 5.25 moles of CH3OH?

iVinArrow [24]

First, we write the reaction for CH3OH combustion

CH3OH+3/2O2--->CO2+2H2O

for 1 mole of methanol, we get 1 mole of CO2, therefore for 5,25 moles of methanol we will get 5,25 moles of CO2

4 0

3 years ago

When an exothermic reaction occurs in a water solution, the temperature of the solution

iVinArrow [24]

Answer:

is hot

Explanation:

6 0

3 years ago

Read 2 more answers

A researcher studying the nutritional value of a new candy places a 4.70 g 4.70 g sample of the candy inside a bomb calorimeter

Sauron [17]

Answer : The nutritional Calories per gram of the candy are, 5.36 calories

Explanation :

First we have to calculate the amount of heat.

$q=c\times \Delta T$

where,

q = heat = ?

c = specific heat = $43.90kJ/K$

$\Delta T$ = change in temperature = $2.41^oC=2.41K$

Now put all the given values in the above formula, we get:

$q=43.90kJ/K\times 2.41K$

$q=105.799kJ$

Now we have to calculate the heat for per gram of sample.

Heat = $\frac{105.799kJ}{4.70g}=22.51kJ/g=22510J/g$

Now we have to calculate the heat in terms of calories.

As, 1 nutritional Calories = 1000 calories

and, 1 calories = 4.2 J

As, 4.2 J = 1 calories

So, 22510 J = $\frac{22510J}{4.2J}\times \frac{1}{1000}cal=5.36cal$

Therefore, the nutritional Calories per gram of the candy are, 5.36 calories

5 0

3 years ago