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nordsb [41]
3 years ago
15

The weight of a table as measured by a student is 20 kg.The

Chemistry
2 answers:
Lera25 [3.4K]3 years ago
8 0
The answer will be c because you find the Percentage
miskamm [114]3 years ago
7 0
(20/23) times 100 is 87%

now the answer asks for percentage ERROR

100-87 =13

so answer is C
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Consider the reaction below.
AysviL [449]

Answer:

2 e⁻ + Cl₂(g) → 2 Cl⁻(aq)

Explanation:

Let's consider the following balanced redox equation.

2 I⁻(aq) + Cl₂(g) → 2 Cl⁻(aq) + I₂(aq)

We can identify 2 half-reactions:

Oxidation: 2 I⁻(aq) → I₂(aq) + 2 e⁻

Reduction: 2 e⁻ + Cl₂(g) → 2 Cl⁻(aq)

We can identify the second half-reaction as the reduction reaction because Cl₂ gains 2 electrons and its oxidation number decreases from 0 to 1-.

6 0
3 years ago
A plane traveled west for 4.0 hours and covered a distance of 4,400 kilometers. What was its velocity?
Softa [21]

Answer:

1,100 km/h

Explanation:

Velocity = distance/time = 4,400 km / 4.0 h = 1,100 km/h

3 0
4 years ago
Read 2 more answers
Which of the following is an example of an atom "following" the octet rule?
lukranit [14]
B) A nitrogen atom that has 5 valence electrons gains 3 more electrons to become a nitride (N3-)
6 0
4 years ago
5.54 moles of AgNO3 are dissolved in 0.48 L of water. What is the molarity of the AgNO, solution?
expeople1 [14]

Answer:

11.54 M

Explanation:

In this case, all we have to do is to apply the following expression:

M = n/V

M: molarity

n: moles

V: volume of solution in liters

In this case, we can assume that the volume of water will be the volume of solution. This is because the problem is not specifing if the moles of AgNO3 are liquid or solid, so we can make a safe assumption of the volume.

Using the expression above we have:

M = 5.54 / 0.48

M = 11.54 M

This is the molarity of solution

7 0
3 years ago
Read 2 more answers
How many moles are in 1.9 x 1046 atoms of chromium?
faust18 [17]

Answer:

<h2>3.156 × 10²² atoms</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{1.9 \times  {10}^{46} }{6.02 \times  {10}^{23} }  \\  = 3.156 \times  {10}^{22}

We have the final answer as

<h3>3.156 × 10²² atoms</h3>

Hope this helps you

8 0
3 years ago
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