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iren2701 [21]
3 years ago
6

Consider two gases, A and B, which are in a container at room temperature. What effect will the following changes have on the ra

te of the reaction between these gases?
The temperature is decreased at a constant volume.

A. Increase
B. Decrease
Chemistry
1 answer:
Mandarinka [93]3 years ago
8 0

Answer:

A. The rate of reaction will increase or go up

B. The rate of reaction will decrase or go down.

Explanation:

Increasing the temperature will make the gas particles move faster. Faster movement will increase rate of collision between particles to cause a reaction. Decreasing the temperature will cause the opposite to happen.

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Answer:

kinetic energy

Explanation:

all moving objects have kinetic energy. when an object is an motion it changes its position by moving in a direction: up,down, forward, or backward

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3 years ago
What does a measure of Xll on the Modified Mercalli scale indicate?
Alborosie

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6 0
3 years ago
A 3.96x10^-24 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000-cm cuvet; a blank solution containi
viktelen [127]

Actual question from source:-

A 3.96x10-4 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000 cm cuvette.  A blank had an absorbance of 0.029.  The absorbance of an unknown solution of compound A was 0.375.  Find the concentration of A in the unknown.

Answer:

Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}

Explanation:

According to the Lambert's Beer law:-

A=\epsilon l c

Where, A is the absorbance

 l is the path length  

\epsilon is the molar absorptivity

c is the concentration.  

Given that:-

c = 3.96\times 10^{-4}\ M

Path length = 1.000 cm

Absorbance observed = 0.624

Absorbance blank = 0.029

A = 0.624 - 0.029 = 0.595

So, applying the values in the Lambert Beer's law as shown below:-

0.595=\epsilon\times 1.000\ cm\times 3.96\times 10^{-4}\ M

\epsilon=\frac{0.595}{3.96\times 10^{-4}}\ {Ms}^{-1}=1502.53\ {Ms}^{-1}

<u>Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}</u>

4 0
4 years ago
The formula C2H4 can be described as
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It's describe as Ethylene
4 0
4 years ago
Read 2 more answers
The transition from the gas phase directly to the solid phase is called:
solmaris [256]
The answer is depostion
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