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Tomtit [17]
2 years ago
13

A sample of strontium bicarbonate weighs 5.0020 mg. How many oxygen atoms are in the sample? I have the answer, but don't unders

tand how to get there.
Chemistry
1 answer:
hodyreva [135]2 years ago
5 0

There are 14.4 * 10^18 oxygen atoms in 5.0020 mg of  strontium bicarbonate.

Mass of strontium bicarbonate Sr(HCO3)2 = 5.0020 mg

Molar mass of strontium bicarbonate Sr(HCO3)2 = 209.6537 g/mol

Number of moles of strontium bicarbonate Sr(HCO3)2 = 5.0020 * 10^-3g/209.6537 g/mol

= 2.3858 * 10^-5 moles

Given that we have 6 oxygen atoms per molecule of Sr(HCO3)2, the total number of oxygen atoms in Sr(HCO3)2 becomes;

2.3858 * 10^-5 moles * 6.02 * 10^23 = 14.4 * 10^18 oxygen atoms

Learn more: brainly.com/question/9743981

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Answer: Fe - O


Explanation:


1) Start by showing the chart information in a more understandable way:


Elements ---------- Electronegativity


aluminum (Al) ----- 1.61


calcium (Ca) ------- 1


carbon (C) ---------- 2.55


chlorine (Cl) -------- 3.16


fluorine (F) --------- 4


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3) Analysis


i) The higher the electronegativity difference between two non-metal elements, the the more the polar the covalent bond. Therefore, the bond H - S is the most polar among the non-metal - non-metal bonds listed. But 0.38 is a small difference, so this is not very polar.


ii) For metal - non-metal bonds, when the difference in electronegativities is too high (close to or greater than 2.0) the ionic character is dominant, and so you cannot classify the bond as polar but as ionic. Therefore, Ca - Cl with 2.16 electronegativity difference is a ionic bond.


iii) The bond in Fe – O has electronegativty difference of 1.61, so it is yet covalent, and highly polar.


Read more on Brainly.com - brainly.com/question/1309389#readmore


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