4.053g<br> 4.2 mL<br> =<br> Please help

Grey Goose ® vodka has an alcohol content of 40.0 % (v/v). Assuming that vodka is composed of only ethanol and water answer the

Vitek1552 [10]

Explanation:

Grey Goose vodka has an alcohol content of 40.0 % (v/v).

Volume of vodka = V = 100 mL

This means that 40.0 mL of alcohol is present 100 mL of vodka.

Volume of ethanol=V' = 40.0 mL

Mass of ethanol = m

Density of the ethanol = d = 0.789 g/mL

$m=d\times V' = 0.789 g/ml\times 40.0 mL=31.56 g$

Volume of water = V''= 100 ml - 40.0 mL = 60.0 mL

Mass of water = m'

Density of the water = d' = 1.00 g/mL

$m'=d'\times V'' = 1.00 g/ml\times 60.0 mL=60.0 g$

a.)

Moles of ethanol = n= $\frac{31.56 g}{46g/mol}=0.6861 mol$

Volume of vodka = V = 100 mL = 0.100 L ( 1mL=0.001 L)

Molarity of the ethanol:

$=\frac{0.6861 mol}{0.100 L}=6.861 M$

6.861 M the molarity of ethanol in this vodka.

b) Mass of ethanol = 31.56 g

Moles of ethanol = n= $\frac{31.56 g}{46g/mol}=0.6861 mol$

Volume of vodka = V = 100 mL

Mass of vodka = m

Density of the water = D = 0.935 g/mL

$M=D\times V=0.935 g/ml\times 100 ml=93.5 g$

The percent by mass of ethanol % (m/m):

$\frac{31.56 g}{93.5 g}\times 100=33.75\%$

33.75% is the percent by mass of ethanol % (m/m) in this vodka.

c)

Moles of ethanol = n= $\frac{31.56 g}{46g/mol}=0.6861 mol$

Mass of solvent that is water = 60.0 g = 0.060 kg ( 1g = 0.001 kg)

Molality of ethanol in vodka :

$m=\frac{0.6861 mol}{0.060 kg}=11.435 m$

11.435 m is the molality of ethanol in this vodka.

d)

Moles of ethanol = $n_1=\frac{31.56 g}{46g/mol}=0.6861 mol$

Moles of water = $n_2=\frac{60.0 g}{18 g/mol}=3.333 mol$

Mole fraction of ethanol = $\chi_1$

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.6861 mol}{0.6861 mol+3.333 mol}$

= 0.1707

Mole fraction of water = $\chi_2$

$\chi_2=\frac{n_2}{n_1+n_2}=\frac{3.3333 mol}{0.6861 mol+3.333 mol}$

= 0.8290

e)

The vapor pressure of vodka = P

Mole fraction of ethanol = $\chi_1=0.1707$

Mole fraction of water = $\chi_2=0.8290$

The vapor pressures of ethanol = $p_1=45.0 Torr$

The vapor pressures of pure water = $p_2=23.8Torr$

$P=\chi_1\times p_1+\chi_2\times p_2$

$P=0.1707\times 45.0torr+0.8290\times 23.8 Torr=27.41 torr$

The vapor pressure of vodka is 27.41 Torr.

5 0

3 years ago

Write the full unabbreviated electrons configuration of the following elements

I am Lyosha [343]

Answer:

Explanation:

Sodium:

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

Iron:

Fe₂₆= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶

Bromine:

Br₃₅ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁵

Barium:

Ba₅₆ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s²

Cobalt:

Co₂₇ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁷

Silver:

Ag₄₇ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s¹ 4d¹⁰

Tellurium:

Te₅₂= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁴

Radium:

Ra₈₈ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰ 6p⁶ 7s²

7 0

4 years ago

What makes carcinogens so dangerous? A. They can be used to make weapons. B. They are extremely toxic to the environment. C. The

rosijanka [135]

The answer is c. they cause cancer

6 0

3 years ago

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4. 200 mL of a 5.6M solution to BaCl_2 have 750 mL of water added to it. What is the new concentration?

IceJOKER [234]

Answer:

4. 1.18 mol·L⁻¹

14. See below.

Explanation:

4. Dilution calculation

V₁c₁ = V₂c₂

Data:

V₁ = 200 mL; c₁ = 5.6 mol·L⁻¹

V₂ = 950 mL; c₂ = ?

Calculation:

c₂ = c₁ × V₁/V₂

c₂ = 5.6 mol·L⁻¹ × (200/950) = 1.18 mol·L⁻¹

The new concentration is 1.18 mol·L⁻¹ .

14. Boyle's Law graphs

We can write Boyle's Law as

pV = k or p = k/V or V= k/p

p and V are inversely related.

(a) As pressure increases, volume decreases. Thus, a graph of V vs p is a hyperbola.

(b) p = k/V =k(1/V)

1/V = (1/k)p

y = m x + 0

A graph of 1/V vs p is a straight line.

4 0

3 years ago

A mixture is two or more substances that are mixed together but not chemically combined. The substances in a mixture each keep t

mestny [16]

The answer is B because salt is NaCl.

8 0

4 years ago

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4.053g 4.2 mL = Please help