First calculate for the molar mass of the given formula unit, CaCO₃. This can be done by adding up the product when the number of atom is multiplied to its individual molar mass as shown below.
molar mass of CaCO₃ = (1 mol Ca)(40 g Ca/mol Ca) + (1 mol C)(12 g of C/1 mol of C) + (3 mols of O)(16 g O/1 mol O) = 100 g/mol of CaCO₃
Then, divide the given amount of substance by the calculated molar mass.
number of moles = (20 g)(1 mol of CaCO₃/100 g)
number of moles = 0.2 moles of CaCO₃
<em>Answer: 0.2 moles</em>
The silver chloride electrode usually functions as a redox electrode where the equilibrium is achieved between silver and its salt (silver chloride).
The half reaction for this electrode is as follow:
<span>AgCl(s)+e−→Ag(s)+Cl−(aq) where:
</span>(s) refers to solid state
(aq) refers to the aqueous state and
e- is the electron
Mass of C = 12g
mass of H = 1g
mass of O = 16g
mass of C2H5OH = 46g = 1 mole
1 mole of C2H5OH ------------ 46g
x moles of C2H5OH ----------- 230g
x = 5 moles of C2H5OH
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of C = 12g
mass of H = 1g
mass of C2H4 = 28g = 1 mole
1 mole of C2H4 -------------- 28g
x moles of C2H4 ------------- 560g
x = 20 moles of C2H4
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mass of S = 32g
mass of O = 16g
mass of SO2 = 64g = 1 mole
1 mole of SO2--------------------- 64g
x mole of SO2 -------------------- 0,64g
x = 0,01 moles of SO2
The answer is D.
"a heterogeneous mixture and a suspension"
