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Nady [450]
3 years ago
5

1.75 M hydrochloric acid is used in a titration with 47.8ml of sodium hydroxide, at the equivalence points 29.3ml of acid was ad

ded. How many moles of acid (H+) have been neutralized in this titration?
Chemistry
1 answer:
Bad White [126]3 years ago
3 0

Answer:

0.0512 mol

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity  

V = volume of solution in liter ,

n = moles of solute ,

From the question ,

Moles of hydrochloric acid is to be calculated ,

Molarity of hydrochloric acid = 1.75 M

Volume of hydrochloric acid = 29.3 ml

1 ml = 1 / 1000 L

Volume of hydrochloric acid = 29.3 ml /1000 = 0.0293 L

Using the above formula to calculate moles -

M = n / V

n = M * V

n = 1.75 M * 0.0293 L = 0.0512 mol

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<u>Answer:</u> 6.57 L of solution can be made.

<u>Explanation:</u>

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

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Given values:

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