Answer:
Grams of water can be heated from 20.0°C to 75°C using 12500.0 Joules = 54.3 g
Explanation:
Heat required to increase temperature
H = mcΔT
m = mass of material
C = specific heat of material
ΔT = Change in temperature.
Here we need to find how many grams of water can be heated from 20.0°C to 75°C using 12500.0 Joules
That is
H = 12500 J
Specific heat of water, C = 4186 J/kg°C
ΔT = 75 - 20 = 55
Substituting
12500 = m x 4186 x 55
m = 0.0543 kg
m = 54.3 g
Grams of water can be heated from 20.0°C to 75°C using 12500.0 Joules = 54.3 g
PART A)
As we know that energy of light depends on its wavelength and frequency as following formula
![E = \frac{hc}{\lambda} = h\nu](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda%7D%20%3D%20h%5Cnu)
now we know that wavelength of blue light is less than the red light so here energy of blue light will be more
also we know that
![\nu = \frac{c}{\lambda}](https://tex.z-dn.net/?f=%5Cnu%20%3D%20%5Cfrac%7Bc%7D%7B%5Clambda%7D)
so here if wavelength is smaller for blue light so its frequency will be high and the speed of both light will be same in same medium
PART B)
Since we know that frequency of blue light is more than red light as well as wavelength of blue light is less than the wavelength of blue light so here blue light will have more energy
When blue light and red light strike the metal surface then due to more energy of blue light it will release some loosely bonded electrons from metal surface which will contribute in current.
here if we increase the intensity of light then the number of photons that contain the blue light of certain energy will be more and that will contribute more current
So here quantification help as we know that due to quantization only certain frequency or energy will lead to eject electron so all colours will not give this current
Answer:
330 m/s
Explanation:
The sound wave has to travel TO the cliff AND back = 2 * 49.5 = 99 m
magnitude of velocity = distance / time = 99m / .3 s = 330 m/s
This would be more of a chemistry question. Remember magnesium has a charge of 2+, and would need to hand off its two extra electrons. Fluorine can only take one electron at a time, so there needs to be two fluorines to take one magnesium's 2 electrons.
With lithium, it has a +1 charge, so it has one extra electron, which it can hand off to just 1 fluorine atom.
Another way of looking at this is:
![Mg^{2+}](https://tex.z-dn.net/?f=%20Mg%5E%7B2%2B%7D%20)
+ 2
![F^{-}](https://tex.z-dn.net/?f=%20F%5E%7B-%7D%20)
= MgF2 (the charges must balance out to zero)
![Li^{+}](https://tex.z-dn.net/?f=%20Li%5E%7B%2B%7D%20)
+
![F^{-}](https://tex.z-dn.net/?f=%20F%5E%7B-%7D%20)
= LiF (the charges balance out to zero)
Answer:
The radius of the curve that Car 2 travels on is 380 meters.
Explanation:
Speed of car 1, ![v_1=65\ km/h](https://tex.z-dn.net/?f=v_1%3D65%5C%20km%2Fh)
Radius of the circular arc, ![r_1=95\ m](https://tex.z-dn.net/?f=r_1%3D95%5C%20m)
Car 2 has twice the speed of Car 1, ![v_2=130\ km/h](https://tex.z-dn.net/?f=v_2%3D130%5C%20km%2Fh)
We need to find the radius of the curve that Car 2 travels on have to be in order for both cars to have the same centripetal acceleration. We know that the centripetal acceleration is given by :
![a=\dfrac{v^2}{r}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv%5E2%7D%7Br%7D)
According to given condition,
![\dfrac{v_1^2}{r_1}=\dfrac{v_2^2}{r_2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bv_1%5E2%7D%7Br_1%7D%3D%5Cdfrac%7Bv_2%5E2%7D%7Br_2%7D)
![\dfrac{65^2}{95}=\dfrac{130^2}{r_2}](https://tex.z-dn.net/?f=%5Cdfrac%7B65%5E2%7D%7B95%7D%3D%5Cdfrac%7B130%5E2%7D%7Br_2%7D)
On solving we get :
![r_2=380\ m](https://tex.z-dn.net/?f=r_2%3D380%5C%20m)
So, the radius of the curve that Car 2 travels on is 380 meters. Hence, this is the required solution.