12 divided by 2/5 is 30.
The difference between 764.7 and 45.39 is 719.31.
:)
Work, Kinetic Energy and Potential Energy
6.1 The Important Stuff 6.1.1 Kinetic Energy
For an object with mass m and speed v, the kinetic energy is defined as K = 1mv2
2
(6.1)
Kinetic energy is a scalar (it has magnitude but no direction); it is always a positive number; and it has SI units of kg · m2/s2. This new combination of the basic SI units is
known as the joule:
As we will see, the joule is also the unit of work W and potential energy U. Other energy
1joule = 1J = 1 kg·m2 (6.2) s2
units often seen are:
6.1.2 Work
1erg=1g·cm2 =10−7J 1eV=1.60×10−19J s2
When an object moves while a force is being exerted on it, then work is being done on the object by the force.
If an object moves through a displacement d while a constant force F is acting on it, the force does an amount of work equal to
W =F·d=Fdcosφ (6.3)
where φ is the angle between d and F.
The work done on the box by the applied force is zero.
The work done by the force of gravity is 75.95 J
The work done on the box by the normal force is 75.95 J.
<h3>The given parameters:</h3>
- Mass of the box, m = 3.1 kg
- Distance moved by the box, d = 2.5 m
- Coefficient of friction, = 0.35
- Inclination of the force, θ = 30⁰
<h3>What is work - done?</h3>
- Work is said to be done when the applied force moves an object to a certain distance
The work done on the box by the applied force is calculated as;
where;
a is the acceleration of the box
The acceleration of the box is zero since the box moved at a constant speed.
The work done by the force of gravity is calculated as follows;
The work done on the box by the normal force is calculated as follows;
Learn more about work done here: brainly.com/question/8119756
I think you subtract to see how much of the mirror is visible if so it is 1.9 hope this helps!!!
Answer:
volume of the airspace=0.605m^3
Explanation:
Patm = 10^5 N/m^2
Depth= 60 metres
Pressure at the depth = ?
Density = 1.025 g/cm3 = 1025 kg/m3
P = Patm + hσg
P = 10^5 + 60*1025*9.8
P = 702700 N/m^2
P = 7.027 atm
Since the temperature is constant, Boyle’s law holds
P1V1 = P2V2
P1 = 1 atm
P1, initial pressure of the bell(atm pressure) = 1 atm
The initial volume of the airspace, V1 = 4.25 m^3
Final pressure at the depth = 7.027 atm
Applying the Boyle’s lay
1*4.25 = 7.027 * V2
V2 = 4.25/7.027
V2 = 0.605m^3
