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amm1812
3 years ago
13

Help me please! Very much appreciated :) Why are standards of mass necessary?

Physics
2 answers:
tia_tia [17]3 years ago
6 0

Answer:

A measurement standard is a quantity that people agree to use as a comparison. Standards are important because they allow measurements to be compared even if different people in different parts of the world take them.

Hope this helps ⊂◉‿◉つ

enot [183]3 years ago
5 0

Answer: The answer is down bellow, plus it's simple

Explanation:What is a measurement standard and why is it important? A measurement standard is a quantity that people agree to use as a comparison. Standards are important because they allow measurements to be compared even if different people in different parts of the world take them.

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1.<br>What is measurement?<br>​
hoa [83]

Answer:

the action of measuring something.

4 0
3 years ago
What is in between the nucleus and the electrons in an atom?
hoa [83]

Answer:

D. Empty Space

Explanation:

4 0
3 years ago
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8~\mathrm{m/s^2}g=9.8 m/s ​2 ​​ ) towards the Eart
Wittaler [7]

Answer:

The centripetal acceleration as a multiple of g=9.8 m/s^{2} is 1.020x10^{-3}m/s^{2}

Explanation:

The centripetal acceleration is defined as:

a = \frac{v^{2}}{r}  (1)

Where v is the velocity and r is the radius

Since the person is standing in the Earth surfaces, their velocity will be the same of the Earth. That one can be determined by means of the orbital velocity:

v = \frac{2 \pi r}{T}  (2)

Where r is the radius and T is the period.

For this case the person is standing at a latitude 71.9^{\circ}. Remember that the latitude is given from the equator. The configuration of this system is shown in the image below.

It is necessary to use the radius at the latitude given. That radius can be found by means of trigonometric.

\cos \theta = \frac{adjacent}{hypotenuse}

\cos \theta = \frac{r_{71.9^{\circ}}}{r_{e}} (3)

Where r_{71.9^{\circ}} is the radius at the latitude of 71.9^{\circ} and r_{e} is the radius at the equator (6.37x10^{6}m).

r_{71.9^{\circ}} can be isolated from equation 3:

r_{71.9^{\circ}} = r_{e} \cos \theta  (4)

r_{71.9^{\circ}} = (6.37x10^{6}m) \cos (71.9^{\circ})

r_{71.9^{\circ}} = 1.97x10^{6} m

Then, equation 2 can be used

v = \frac{2 \pi (1.97x10^{6} m)}{24h}

Notice that the period is the time that the Earth takes to give a complete revolution (24 hours), this period will be expressed in seconds for a better representation of the velocity.

T = 24h . \frac{3600s}{1h} ⇒ 84600s

v = \frac{2 \pi (1.97x10^{6} m)}{84600s}

v = 146.31m/s

Finally, equation 1 can be used:

a = \frac{(146.31m/s)^{2}}{(1.97x10^{6}m)}

a = 0.010m/s^{2}

Hence, the centripetal acceleration is 0.010m/s^{2}

To given the centripetal acceleration as a multiple of g=9.8 m/s^{2}​ it is gotten:

\frac{0.010m/s^{2}}{9.8 m/s^{2}} = 1.020x10^{-3}m/s^{2}

6 0
3 years ago
Un coche de unos 500 kg viaja a 90 km/h. Percibe un obstáculo y debe frenar a tope. Por las marcas del suelo se sabe que el espa
a_sh-v [17]

Answer:

THERE'S A GIRL WHO WILL STEAL YOUR INFO, PLZ DON"T PRESS THE LINK IF SHE ASKS YOU TOO!!!!!

Explanation:

3 0
3 years ago
A nichrome wire has a resistance of 5
kari74 [83]

Answer:

R = 6.67 Ohm's

Explanation:

Resistance is a property of a material that measures the opposition to the flow of current through the material. It is measured in Ohm's.

              R = (ρl) ÷ A

where; R is the resistance of the material, A is its cross sectional area, l is its length and ρ is its resistivity.

For the first nichrome wire, resistance is 5 Ohm's.

i.e            R = (ρl) ÷ A = 5 Ohm's

For the second nichrome wire, length = 4l, and area of cross section = 3A. The resistance of the second wire can be determined by;

R = (4ρl) ÷ 3A

   = \frac{4}{3} {(ρl) ÷ A}

   =  \frac{4}{3} × 5

R = 6.67 Ohm's

Resistance of the second nichrome wire is  6.67 Ohm's.

4 0
3 years ago
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