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amm1812
3 years ago
13

Help me please! Very much appreciated :) Why are standards of mass necessary?

Physics
2 answers:
tia_tia [17]3 years ago
6 0

Answer:

A measurement standard is a quantity that people agree to use as a comparison. Standards are important because they allow measurements to be compared even if different people in different parts of the world take them.

Hope this helps ⊂◉‿◉つ

enot [183]3 years ago
5 0

Answer: The answer is down bellow, plus it's simple

Explanation:What is a measurement standard and why is it important? A measurement standard is a quantity that people agree to use as a comparison. Standards are important because they allow measurements to be compared even if different people in different parts of the world take them.

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What is similar about the primary structure of each protein? (The proteins are eggs, milk, and meat)
Usimov [2.4K]

Answer:

Explanation:

are these 3 questions?

4 0
4 years ago
A child holds onto a string attached to a toy boat and exerts a force of 7.5 N to pull the boat a distance of 9.2 m a long a str
soldi70 [24.7K]

The work that need to do is 66.24 J.

<h3>Explanation :</h3>

Hello guys, before we can count how much the work that needed to pull the toy, we should know how formula to count it first. Because the movement is with the angle, so the formula is :

\boxed {\bold {W = F \times s \times \cos(\theta)}}

If :

  • W = work (J)
  • F = force (N)
  • s = shift (m)
  • θ = elevation angle (°)

We know that :

  • x = the horizontal shift = 9,2 m
  • θ = elevation angle = 15°

W = work = ... J

W = F \times s \times \cos(\theta) \\ W = 7.5 \times 9.2 \times \cos(15) \\ W = 69 \times 0.96 = 66.24 \: J

So, the work that need to do is 66.24 J.

<u>Subject</u><u> </u><u>:</u><u> </u><u> </u><u>Physics</u><u> </u>

<u>Class</u><u> </u><u>:</u><u> </u><u>Junior</u><u> </u><u>High</u><u> </u><u>School</u><u>/</u><u>Senior</u><u> </u><u>High</u><u> </u><u>School</u><u> </u>

<u>Keyword</u><u> </u><u>:</u><u> </u><u>Work</u><u>;</u><u> </u><u>Force</u><u>;</u><u> </u><u>Shift</u><u>;</u><u> </u><u>and</u><u> </u><u>Elevation</u><u> </u><u>Angle</u><u> </u>

5 0
4 years ago
a 45kg boy is holding a 12kg pumpkin while standing on ice skates on a smooth frozen pond. the boy tosses the pumpkin with a hor
irga5000 [103]
Let's split the problem into two parts, and let's solve it by using conservation of momentum.

1) Let's analyze the moment when the boy tosses the pumpkin. Before this moment, the boy is standing with the pumpkin, so with speed v=0 and therefore the total momentum of the system (boy+pumpkin) is zero.
After he tosses the pumpkin, the boy will start to move with speed v_b and the pumpkin starts to move with speed v_p=2.8 m/s. The momentum of the boy is m_b v_b (with m_b =45 kg being the mass of the boy), while the momentum of the pumpkin is m_p v_p (where m_p=12 kg is the mass of the pumpkin). Since the total momentum must be equal to zero (because the total momentum cannot change), then we can write
m_b v_b + m_p v_p =0
From which we find
v_b = - \frac{m_p v_p}{m_b}=- \frac{(12 kg)(2.8 m/s)}{45 kg} =-0.75 m/s
and this is the speed of the boy, and the negative sign means he's moving in the opposite direction of the pumpkin.

2) Now let's focus on the entire system (boy+pumpkin+girl). Initially, the total momentum of this system is zero, because both the boy (holding the pumpkin) and the girl are still. So, the total momentum after the girl catches the pumpkin must be still zero.
After this moment, the boy has a momentum of m_b v_b, while the girl has momentum (m_g+m_p)v_g where m_g=37 kg is the girl mass v_g is the girl speed. Here we use m_g+m_p because the girl is holding the pumpkin now. Therefore, the conservation of momentum becomes
m_bv_b + (m_g+m_p)v_g =0
and so
v_g = - \frac{m_b v_b}{m_g+m_p} =- \frac{(45 kg)(-0.75 m/s)}{37 kg+12 kg} =0.69 m/s
and this is the girl's speed, with positive sign so with same direction of the pumpkin initial direction.
6 0
4 years ago
g As observed on earth, a certain type of bacteria is known to double in number every 24 hours. Two cultures of these bacteria a
tangare [24]

Answer:

86.4 hrs

Explanation:

The amount of bacteria is initially 1

It doubles every 24 hrs.

After first 24 hrs, the amount = 2

After next 24 hrs = 4

After next 24 hrs = 8

After next 24 hrs = 16

After next 24 hrs = 32

After next 24 hrs = 64

After next 24 hrs = 128

After next 24 hrs = 256

Total time taken to reach 256 = 24 x 8 = 192 hrs

For the bacteria culture on the rocket that travels at a speed of 0.893c relative to the earth, this time is contracted by the relationship

t = t'(1 - ¥^2)^0.5

Where t is the contracted time =?

t' is the time on earth

¥ = v/c

Where v is the speed of the rocket

c is the speed of light

since v = 0.893c

¥ = 0.893

Substituting, we have

t = 192 x (1 - 0.893^2)^0.5

t = 192 x 0.2025^0.5

t = 192 x 0.45 = 86.4 hrs

8 0
3 years ago
A 2.0-kg block slides on a rough horizontal surface. A force (magnitude P = 4.0 N) acting parallel to the surface is applied to
irinina [24]

When the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

<h3>Frictional force between the block and the horizontal surface</h3>

The frictional force between the block and the horizontal surface is determined by applying Newton's law;

∑F = ma

F - Ff = ma

Ff = F - ma

Ff = 4 - 2(1.2)

Ff = 4 - 2.4

Ff = 1.6 N

When the applied force increases to 5 N, the magnitude of the block's acceleration is calculated as follows;

F - Ff = ma

5 - 1.6 = 2a

3.4 = 2a

a = 3.4/2

a = 1.7 m/s²

Thus, when the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

Learn more about frictional force here: brainly.com/question/4618599

8 0
2 years ago
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