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3 years ago

In one hour Earth receives enough solar energy to meet the energy needs of the world for

Physics

1 answer:

erastova [34]3 years ago

3 0

I have read that it is enough energy to power the needs of civilization for an entire year.

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The length of a simple pendulum is 0.760 m, the pendulum bob has a mass of 365 grams, and it is released at an angle of 12.0o to

Allushta [10]

Answer:

0.572 Hz

Explanation:

given,

length of simple pendulum, l = 0.76 m

mass of the bob, m = 365 g = 0.365 Kg

angle made from the vertical, = 12°

frequency, f = ?

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{g}{L}}$

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{9.8}{0.76}}$

$f = \dfrac{1}{2\pi}\times 3.59$

f = 0.572 Hz

The frequency at which pendulum vibrates is equal to 0.572 Hz

3 0

4 years ago

What is done when an object is moved by a force

Flauer [41]

1). The object winds up in a different location.

2). Work is done.

7 0

3 years ago

Storage of unlimited quantities of energy in batteries is possible. TrueFalse

dangina [55]

False

It is impossible to get infinite energy let alone to put it inside one battery

3 0

3 years ago

Read 2 more answers

The express train can travel 100 miles per hour. This information describes the train's

Tomtit [17]

Speed. This ONLY includes the miles per hour. If it had a direction it would be velocity.

7 0

4 years ago

Read 2 more answers

A charge Q is to be divided into two parts, labeled 'q' and 'Q-q? What is the relationship of q to Q if, at any given distance,

Lisa [10]

Answer:

Explanation:

The two charges are q and Q - q. Let the distance between them is r

Use the formula for coulomb's law for the force between the two charges

$F = \frac{Kq_{1}q_{2}}{r^{2}}$

So, the force between the charges q and Q - q is given by

$F = \frac{K\left ( Q-q \right )q}}{r^{2}}$

For maxima and minima, differentiate the force with respect to q.

$\frac{dF}{dq} = \frac{k}{r^{2}}\times \left ( Q - 2q \right )$

For maxima and minima, the value of dF/dq = 0

So, we get

q = Q /2

Now $\frac{d^{2}F}{dq^{2}} = \frac{-2k}{r^{2}}$

the double derivate is negative, so the force is maxima when q = Q / 2 .

6 0

4 years ago