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Tanzania [10]
3 years ago
12

Locate the element calcium (Ca) on the periodic table and click on the square. Read about the properties of calcium. Why might c

alcium be important in the diet of many living things?
Physics
2 answers:
Ann [662]3 years ago
6 0
In the periodic table, calcium is located at the 2nd column of the 4th row starting from the hydrogen gas.

Calcium is very essential in the human body is it helps maintain a healthy teeth and all other bones. Other calcium are also found in nerves, tissues, and all other parts. Calcium also helps in clotting blood and normalizing a person's heart beat. This may apply not only to humans but to all living things.
jeka57 [31]3 years ago
3 0

Answer:

Sample Response: Calcium is important in the diet of many living things because it helps form bones and shells.

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A two-slit Fraunhofer interference-diffraction pattern is observed with light of wavelength 672 nm. The slits have widths of 0.0
ololo11 [35]

Answer:

Explanation:

In case of diffraction , angular width of central maxima =2 λ/d

λ is wave length of light and d is slit width

In case of interference , angular width of each fringe

= λ /D

D is distance between two slits

No of interference fringe in central diffraction fringe

=2 λ/d x D/λ = 2 x D /d = 2 x .24/.03 = 16.

6 0
3 years ago
The idea that earth was the center of the universe is an example of ---that has been long dicarded
Leni [432]

Answer:

Geocentric model of the universe

Explanation:

In the geocentric model of the universe, the earth is the center of the universe. This theory was later replaced by the heliocentric model which places the sun as the center.

This belief was propagated by the ancient Greeks. The geocentric model of the universe was proposed by Ptolemy.

The model suggests that other planetary bodies orbits the earth.

4 0
3 years ago
A particle travels clockwise on a circular path of diameter​ R, monitored by a sensor on the circle at point​ P; the other endpo
kotykmax [81]

We make a graphic of this problem to define the angle.

The angle we can calculate through triangle relation, that is,

sin\theta = \frac{c}{QP}\\sin\theta = \frac{c}{R}\\\theta=sin^{-1}\frac{c}{R}

With this function we should only calculate the derivate in function of c

\frac{d\theta}{dc} = \frac{1}{\sqrt{1-\frac{c^2}{R^2}}}(\frac{c}{R})'\\\frac{d\theta}{dc} = \frac{1}{\sqrt{R^2-c^2}}

That is the rate of change of \theta.

b) At this point we need only make a substitution of 0 for c in the equation previously found.

\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{\sqrt{R^2-0}}\\\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{R}

Hence we have finally the rate of change when c=0.

6 0
3 years ago
A biologist looking through a microscope sees a bacterium at r⃗ 1=2.2i^+3.7j^−1.2k^μm(1μm=10−6m). After 6.2 s , it's at r⃗ 2=4.6
stiv31 [10]

The Average velocity for the bacterium is 0.75 unit/sec.

<u>Explanation:</u>

The given values are in the vector form

Where,

dS = distance covered

dT = time interval

Now, to calculate distance covered, we have

|d S|=\sqrt{d S^{2}}

&

d S=r_{2}-r_{1}

d S=(4.6 i+1.9 k)-(2.2 i+3.7 j - 1.2 k)

d S=(4.6-2.2) i+(0-3.7) j+(1.9+1.2) k

d S=2.4 i-3.7 j+3.1 k

Now, putting these values in the standard formula to evaluate the average velocity, we get;

v_{a v g}=\frac{|\mathrm{d} S|}{d T}

v(a v g)=\frac{|\sqrt{\left\{\left(2.4^{2}\right)+\left(3.7^{2}\right)+\left(3.1^{2}\right)\right\}}|}{7.2}

As dT=7.2 sec

Now,

Solving the equation, we get;

v(a v g)=\frac{5.390732789}{7.2}

\begin{aligned}&v(a v g)=\frac{5.39}{7.2}\\&v(a v g)=0.748611111\\&v(a v g)=0.75 \text { units / sec }\end{aligned}

Hence, the average velocity for the bacterium is 0.75 unit/sec.

3 0
3 years ago
I don't get it at all
andrezito [222]
The most i can help with is Saliva glands or salivary glands 
3 0
3 years ago
Read 2 more answers
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