Explanation:
Formula to calculate standard electrode potential is as follows.

= 0.535 - 1.065
= - 0.53 V
Also, it is known that relation between
and K is as follows.

ln K =
Substituting the given values into the above formula as follows.
ln K =
=
ln K = -41.28
K =
= 
Thus, we can conclude that the value of the equilibrium constant for the given reaction is
.
Answer:
The answer will be Ligand A with a dissociation constant (Kd) of
M
Explanation:
When the dissociation constant in the ligand is small (in order of nano) (
) it will be more tied. Due to a dissociation constant measures how much a ligand can be able to be separated from the protein so if the number is small it means that the ligand is highly binded to the protein.
On the other hand, the occupancy percentage of the ligand does not imply binding. Conversely, a High-affinity ligand binding with the proteins implies that a relatively low concentration of a ligand is adequate to occupy the maximum ligand-binding site.
Answer:
The answer to your question is D
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