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ella [17]
3 years ago
5

What is the correct IUPAC name for Mg₃P₂?

Chemistry
1 answer:
Ahat [919]3 years ago
7 0
Magnesium phosphorus - replace with ide because it non metal in periodic table so

Answer : Magnesium phosphide
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The density of gold is 19.3 g/cm3. What is the volume of a 575 gram bar of pure gold?
Gnoma [55]

Answer:

The  answer to your question is: Volume = 29.79 cm³

Explanation:

Data

Density of gold = 19.3 g/cm3

Mass = 575 grams

Formula

density = mass / volume

Volume = mass/density

Volume = 575 g / 19.3 g/cm3

Volume = 29.79 cm³

3 0
4 years ago
Read 2 more answers
What two objects is acceleration dependent on??
asambeis [7]
The two objects are net force and mass. 

The net force is the total amount of force going on one direction, and mass is amount of matter in which it's contained  in a particle/object. 


Hope this helps! 
7 0
3 years ago
What was the contribution of Dobereiner towards classification of elements?​
Liono4ka [1.6K]

<em>that the relative atomic mass of the middle element in each triad was close to the average of the relative atomic masses of the other two elements.</em>

  • <em>This gave other scientists a clue that relative atomic masses were important when arranging the elements.</em>

<h2><em>hope</em><em> </em><em>it</em><em> </em><em>helps!</em></h2>
6 0
2 years ago
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The first law of thermodynamics states that ΔE=Q-W. How is this also a statement of the principle of conservation of energy?
yaroslaw [1]
Hello I took this test just now and got 100% your correct answer would be C. Hope this helps.
4 0
3 years ago
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A 5-kg quantity of radioactive isotope decays to 2 kg after 10 years. Find the decay constant of the isotope.k = _____
Dvinal [7]

Answer:

k = -0.09165 years^(-1)

Explanation:

The exponential decay model of a radioactive isotope is generally given as;

A(t) = A_o(e^(kt))

Where;

A_o is quantity of isotope before decay, k is decay constant and A(t) is quantity after t years

We are given;

A_o = 5 kg

A(10) = 2kg

t = 10 years

Thus;

A(10) = 2 = 5(e^(10k))

Thus;

2 = 5(e^(10k))

2/5 = (e^(10k))

0.4 = (e^(10k))

In 0.4 = 10k

-0.9164 = 10k

k = -0.9164/10

k = -0.09165 years^(-1)

7 0
3 years ago
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