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2 years ago

Some help me plss????

Mathematics

2 answers:

barxatty [35]2 years ago

8 0

(-9,11) would be your answer!!!!

raketka [301]2 years ago

7 0

Answer:

[-9,11]

Step-by-step explanation:

The domain is the x values that the line is on, basically. You use brackets because the points are included.

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The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu

rjkz [21]

The balloon has a volume $V$ dependent on its radius $r$ :

$V(r)=\dfrac43\pi r^3$

Differentiating with respect to time $t$ gives

$\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}$

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

$10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}$

The surface area of the balloon is

$S(r)=4\pi r^2$

and differentiating gives

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}$

so that at the moment the radius is 3 m, its area is increasing at a rate of

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}$

4 0

2 years ago

Make v the subject of the relation KE = ½mv²

Irina18 [472]

Answer:

$v=\sqrt{\frac{2KE}{m} }$

Step-by-step explanation:

$KE = 1/2mv^2$

$KE/1/2=mv^2$

$2KE=mv^2$

$2KE/m=v^2$

$\sqrt{2KE/m} =v$

7 0

3 years ago

Read 2 more answers

Please explain if you can. And don’t say to Google it.

Marrrta [24]

So the coordinates are written (x,y) so if you have a graph you would oput the first dot at 1 over,2 up as x avis is the horizontal axis and y is vertical, then your next dot would be three over ,10 up and then your last dot would be 5 over and 18 up, your intercept is where your line meets your axis

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3 years ago

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Which of these is greatest number that rounds to 9?

Sonja [21]

If anything is above 5 it will round up

3 0

3 years ago

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Using the approximation 3.14 for \pi what is the radius of a circle with circumference 75.4m

Charra [1.4K]

Answer:

The radius of the circle is 12.006 m.

Step-by-step explanation:

Let us assume the radius of the circle = r

Circumference = 75.4 m

Now, CIRCUMFERENCE OF A CIRCLE = 2 π r

⇒ 75 .4 m = 2 π r

Now, putting π = 3.14, we get:

75 .4 m = 2 (3.14) r

⇒ 75.4 = 6. 28 r

or, r = 75.4/6.28 = 12.006

or, r = 12.006 m

Hence, the radius of the circle with circumference 75.4 m is 12.006 m.

3 0

3 years ago