So since m is on both sides of the equal sign, they cancel each other out. Then multiply both sides by 2, so you get 2gh = v². Then (I'm assuming) g = acceleration due to gravity = 9.80 m/s². If you multiply it by the two, you get 19.6 m/s². I'm assuming h is the height, in meters. If you have the number for h, plug it in now and multiply that. You'll get some number x that has a value of m²/s². Since you're looking for v, and right now you only have v², take the square root of both sides of your equation and that'll give you the answer. If you don't have a value for h, though, just write your answer like √(2gh) = v or whatever format like that your teacher usually wants, and you should be good. I don't know how far the teacher wants you to simplify or solve this, but hopefully this gives you what you need! :)
Answer:
The truck
Explanation:
Kinetic energy is directly proportional to mass. Since the truck has more mass, it will have more energy.
Answer:
a) 1200 kN/m²
b) 1,200,000 kg/ms²
c) 1.2 × 10⁹ kg/km.s²
Explanation:
Given:
Pressure = 1200 kPa
a) 1 Pa = 1 N/m²
thus,
1000 N = 1 kN
1200 kPa = 1200 kN/m²
b) 1 Pa = 1 N/m² = 1 kg/ms²
Thus,
1200 kPa = 1200000 Pa
or
1200000 Pa = 1200000 × 1 kg/ms²
or
= 1,200,000 kg/ms²
c) 1 km = 1000 m
or
1 m = 0.001 Km
thus,
1,200,000 kg/ms² =
or
= 1.2 × 10⁹ kg/km.s²
Answer:
Part a)

Part b)

Part d)
As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different
On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.
Explanation:
Part a)
By Guass law we know that



Part b)
Outside the outer cylinder we will again use Guass law



Part d)
As we know that due to induction of charge there will be same charge appear on the inner and outer surface of the cylinder but the sign of the charge must be different
On the inner side of the cylinder there will be negative charge induce on the inner surface and on the outer surface of the cylinder there will be same magnitude charge with positive sign.