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Tju [1.3M]
3 years ago
6

Find the acceleration of a train whose speed increases from 9 m/s to 22 m/s in 160s

Physics
1 answer:
Rainbow [258]3 years ago
6 0
Acceleration = (v2-v1) / (t2-t1) = (22-9) / 160 = 13/160 m/s
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The speed of an object and the direction in which it moves constitute a vector quantity known as the velocity. an ostrich is run
Orlov [11]
Velocity of an object is its rate of change of the object's position per interval of time. Velocity is a vector quantity which means that it consists of a magnitude and a direction. Magnitude is represented by the speed and the direction is represented by the angle. To determine the velocity components, we use trigonometric functions to determine the angle of the components. For the north component we, use the sine function while, for the west component, we use the cosine function. We calculate as follows:
north velocity component = (16.8 m/s) (sin 54°) = 16.4 m/s
<span>west velocity component = (16.8 m/s) (cos 54°) = 3.49 m/s</span>



6 0
4 years ago
Charges q3 and q5 are now replaced by two charges, q2 and q6, having equal magnitude and sign (-3.4 μC). Charge q2 is located at
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3 0
3 years ago
9. What is the equivalent resistance of the circuit shown in the figure below?
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4 0
3 years ago
The temperature inside a vehicle can rise ____ degrees higher than the outside temperature.
Elis [28]

Answer:

Generally, 40 to 50 degrees

Explanation:

About the heat-up over time, whether the windows of a vehicle are locked or partially open makes very little difference. In both situations, in an internal temperature of a vehicle, even at an outside temperature of only 72 ° F, it may exceed approximately 40 ° F within one hour. This happens mainly due to the greenhouse effect that is the heat inside the car is trapped and not allowed to escape. Thus, raising the temperature of the vehicle.

3 0
3 years ago
The Earth has mass ME and average radius RE. The Moon has mass MM and the average distance from the center of mass of the moon t
marusya05 [52]

Answer:

Moment of inertia of Earth about its own axis is given as

I = 9.7 \times 10^{37} kg m^2

Explanation:

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I = \frac{2}{5}M_eR_e^2

so we will have

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so we have

I = 9.7 \times 10^{37} kg m^2

3 0
3 years ago
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