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2 years ago

How do you produce the inverse of a function?

Mathematics

1 answer:

cricket20 [7]2 years ago

7 0

Nice song lyrics g :)

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Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(3, −6), Q(0, 9), and R(−3, 0). Triangle P'Q'R' has v

Serggg [28]

Step-by-step explanation:

that's for Part B

Part C: triangles PQR and P"Q"R" are not congruent since the corresponding sides are not equal

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2 years ago

A confidence level of 95% mean

USPshnik [31]

Answer:

A 95% confidence interval is a range of values that you can be 95% certain contains the true mean of the population. ... The 95% confidence interval defines a range of values that you can be 95% certain contains the population mean.

Step-by-step explanation:

hope that helps

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3 years ago

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Calculate the slope of the line using two different pairs of points.

mihalych1998 [28]

Rise/run = 20/20 = 1
m = 1

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2 years ago

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HELP ME PLEASE!! Find R and theta with the coordinates (-3,7).

Fofino [41]

Answer:

Since r is the distance from the origin to (x,y), it is the magnitude r=√x2+y2. Alternatively, from the equation (1), one can calculate directly that x2+y2=r2cos2θ+r2sin2θ=r2(cos2θ+sin2θ)=r2.

Step-by-step explanation:

7 0

2 years ago

Find an equation of a line through √3,1 / 2) parallel to the line:

vagabundo [1.1K]

Answer:

(a) $x=\sqrt{3}$

(b) $y=\frac{1}{2}$

(c) Answer of part a is equation of line $x=\sqrt{3}$ which is parallel to y axis and in part by equation of line is $y=\frac{1}{2}$ which is parallel to x axis

Step-by-step explanation:

We have given points are $(\sqrt{3},\frac{1}{2})$

(a) Equation of line is given x = -9

We have to find the equation of line parallel to x= -9 and passing through $(\sqrt{3},\frac{1}{2})$

x = -9 line is parallel to y axis and so slope will be infinite

Equation of line is given by $y-y_1=m(x-x_1)$

So $y-\frac{1}{2}=\frac{1}{0}(x-\sqrt{3})$

$x=\sqrt{3}$

(b) Equation of line is given $y=-\sqrt{7}$

This line is parallel to x axis so slope will be zero

So equation of line will be $y-\frac{1}{2}=0(x-\sqrt{3})$

$y=\frac{1}{2}$

(c) Answer of part a is equation of line $x=\sqrt{3}$ which is parallel to y axis and in part by equation of line is $y=\frac{1}{2}$ which is parallel to x axis

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3 years ago