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valentina_108 [34]
3 years ago
7

CoSO₄ and Pb(NO₃)₂ are mixed in aqueous solution.

Chemistry
1 answer:
laila [671]3 years ago
3 0

Answer:

See below.

Explanation:

<h3>CoSO4 + Pb(NO3) 2 = Co(NO3) 2 + PbSO4</h3>
You might be interested in
4NaCl + 2SO2 + _____H2O + _____O2 → _____Na2SO4 + 4HCl
Alik [6]

The numbers that balance the following equation: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl is 2, 1, 2.

BALANCING EQUATION:

  • Balancing a chemical equation means to make sure that the number of atoms of each element on both sides of the equation are equal.

  • According to this question, the following chemical reaction are given: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl

  • Some of the coefficients (numbers) have been placed there while some are missing. The equation that includes the missing coefficients (numbers) to balance the equation is:

4NaCl + 2SO2 + 2H2O + O2 → 2Na2SO4 + 4HCl

Learn more at: brainly.com/question/21049751?referrer=searchResults

3 0
3 years ago
Epirical formula of P4O10
harina [27]
I would say the answer is P2O5. Some teachers use PO2.5. I'm not one of them.
7 0
4 years ago
WHY DOES SALT SOLUTION GET RUSTED
Dennis_Churaev [7]

The Salt solution acts as an electrolyte, allowing iron to lose electrons more easily and speeds up the rusting process.

6 0
3 years ago
Calculate the molar concentration of OH ions in a 0.066 M solution of ethylamine (C2H5NH2: Kb= 6.4 x 10-)
wel

Answer:

6.5x10⁻³M = [OH⁻]

Explanation:

The Kb of a Weak base as ethylamine is expressed as follows:

Kb = [OH⁻] [C₂H₅NH₃⁺] / [C₂H₅NH₂]

As the equilibrium of ethylenamine is:

C₂H₅NH₂(aq) + H₂O(l) ⇄ C₂H₅NH₃⁺(aq) + OH(aq)

The concentration of C₂H₅NH₃⁺(aq) + OH(aq) is the same because both ions comes from the same equilibrium. Thus, we can write:

Kb = [OH⁻] [C₂H₅NH₃⁺] / [C₂H₅NH₂]

6.4x10⁻⁴ = [X] [X] / [C₂H₅NH₂]

Also, we can assume the concentration of ethylamine doesn't decrease. Replacing:

6.4x10⁻⁴ = [X] [X] / [0.066M]

4.224x10⁻⁵ = X²

6.5x10⁻³M = X

<h3>6.5x10⁻³M = [OH⁻]</h3>
7 0
3 years ago
72.0 grams of water how many miles of sodium with react with it?
Flura [38]

Answer:

\large \boxed{\text{8.00 mol}}

Explanation:

We will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

Mᵣ:                  18.02

            2Na + H₂O ⟶ 2NaOH + H₂

m/g:                72.0  

2. Moles of H₂O

\text{Moles of H$_{2}$O} = \text{72.0 g H$_{2}$O} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{18.02 g  H$_{2}$O}} = \text{3.996 mol H$_{2}$O}

3. Moles of Na

The molar ratio is 2 mol Na/1 mol H₂O.

\text{Moles of Na} =  \text{3.996 mol H$_{2}$O} \times \dfrac{\text{2 mol Na}}{\text{1 mol H$_{2}$O}} = \textbf{8.00 mol Na}\\\\\text{The water will react with $\large \boxed{\textbf{ 8.00 mol}}$ of Na}

7 0
3 years ago
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