All categories

3 years ago

How many hundred thousands are in 749,085

Mathematics

2 answers:

nikklg [1K]3 years ago

3 0

Answer:

7 hundred thousands are in 749,085

Step-by-step explanation:

masya89 [10]3 years ago

3 0

There are 7 hundred thousands in 749, 085. The 7 in the beginning represents the amount of hundreds in the problem.

You might be interested in

What is the value of X ? A-17 B-26 C-39 D-41

Hatshy [7]

Answer:

Step-by-step explanation:

It's a right triangle so

$x^2=40^2+9^2$

x = 41

4 0

3 years ago

i need all of them, if you answer something that isn't the answer/ just farming points you are getting reported

Elanso [62]

Check this out mate!

6 0

3 years ago

Solve for x. −12x+13>35 Drag and drop a number or symbol into each box to correctly complete the solution.

Katen [24]

Answer:

x < -11/6.

Step-by-step explanation:

−12x + 13 > 35

-12x > 35 - 13

-12x > 22

Divide both sides by -12 and invert the inequality sign:

x < -22/12

x < -11/6.

7 0

3 years ago

Julie had $20.00 in her pocket. She spent $7.40. About what percent of her money does she still have?

posledela

63%

First, we have to take 20.00 - 7.40 which gets us 12.60.

Then, we use the formula where we put the 12.60 on top of a fraction bar, and the 20.00 on bottom.

We do 12.60 x 100 which makes 1260.

Lastly, we divide that by the 20.00 which gets us 63.

So, Julie has 63% of her money left.

I hope this helped!!!

4 0

1 year ago

Evaluate the integral Integral ∫ from (1,2,3 ) to (5, 7,-2 ) y dx + x dy + 4 dz by finding parametric equations for the line seg

n200080 [17]

$\vec F(x,y,z)=y\,\vec\imath+x\,\vec\jmath+3\,\vec k$

is conservative if there is a scalar function $f(x,y,z)$ such that $\nabla f=\vec F$ . This would require

$\dfrac{\partial f}{\partial x}=y$

$\dfrac{\partial f}{\partial y}=x$

$\dfrac{\partial f}{\partial z}=3$

(or perhaps the last partial derivative should be 4 to match up with the integral?)

From these equations we find

$f(x,y,z)=xy+g(y,z)$

$\dfrac{\partial f}{\partial y}=x=x+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$f(x,y,z)=xy+h(z)$

$\dfrac{\partial f}{\partial z}=3=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=3z+C$

$f(x,y,z)=xy+3z+C$

so $\vec F$ is indeed conservative, and the gradient theorem (a.k.a. fundamental theorem of calculus for line integrals) applies. The value of the line integral depends only the endpoints:

$\displaystyle\int_{(1,2,3)}^{(5,7,-2)}y\,\mathrm dx+x\,\mathrm dy+3\,\mathrm dz=\int_{(1,2,3)}^{(5,7,-2)}\nabla f(x,y,z)\cdot\mathrm d\vec r$

$=f(5,7,-2)-f(1,2,3)=\boxed{18}$

8 0

3 years ago