Post a picture to see the example of point C
Answer:
not idea sorry but 4 no is idea it can be solve the 10 std
The solution for this problem is:
The population is 500 times bigger since 8000/24 = 500. The population after t days is computed by:P(t) = P₀·4^(t/49)
Solve for t: 8000 = 8·4^(t/49) 1000 = 4^(t/49) log₄(1000) = t/49t = 49log₄(1000) ≅ 244 days
R = 0.9
A value of 0.9 would indicate that the correlation is positive. Since it's also close to the value 1, it would also tell us that the correlation of y and x is strong. Therefore, r = 0.9 would be a strong linear association in which y increases as x increases.
r = -1.0
Since the value of r is negative, this would mean that the correlation is also negative. Furthermore, the value of r is also at the minimum point which is -1.0 thus this would tell us that the correlation is a perfect linear association in which y decreases as x increases.
r = -0.6
Likewise, this r value is also negative thus allowing us to know that y will decrease as x increases. The value of r, which is -0.6, is also close to -1.0. This allows us to tell that it is a strong relationship. Therefore, r = -0.6 is a strong linear association in which y decreases as x increases.
r = 0.1
For this correlation, the r value is positive. This would indicate that the value of y will increase as x increases. Since the r value is only 0.1, we cannot say that it is a strong relationship since it is far from the maximum value for a perfect relationship which is 1. Therefore, r = 0.1 is a moderate linear association in which y increases as x increases.
Answer:
The population of the town is 0.983 times the population of the town in the previous year.
B is correct.
Step-by-step explanation:
We are given a function which represent population of a town after t years.
It is an exponential function. Exponential function wither decease or increase it depends on factor.
b is factor which decides factor of exponential function decrease or increase.
- If b >1 then function increase
- If 0<b<1 then function decrease.
If we see our problem
Here, b=0.983<1
Function would be decrease by factor of 0.983
Thus, The population of the town is 0.983 times the population of the town in the previous year.
