<img src="https://tex.z-dn.net/?f=%28x%2B2y%29x%5E%7B3%7D" id="TexFormula1" title="(x+2y)x^{3}" alt="(x+2y)x^{3}" align="absmidd

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bearhunter [10]

2 years ago

le" class="latex-formula">

Mathematics

2 answers:

BartSMP [9]2 years ago

8 0

Simplify the expression. answer= x^4 + 2yx^3

Nookie1986 [14]2 years ago

7 0

The answer is x^4 + 2x^3y

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The critical points of a rational inequality are –1, 3, and 4. Which set of points can be tested to solve the inequality? x = 1

never [62]

Answer:

x=-3, x=1, x=3.5, and x=5

Step-by-step explanation:

Given the critical points (turning points) which represent the maximum or the minimum points, the set of points that can be tested to solve the inequality will consist of points to the right and to the left of these points. The set of points that solve the inequality will be simply the points where the graph of the function crosses the x-axis. From these information, the set of points will be as given above

4 0

3 years ago

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What is the reciprocal of 3 and 1/5

Vaselesa [24]

1/3 and 5 because 3/1 is three and 1/3 is the opposite while 1/5 is 5/1 which is 5.

4 0

3 years ago

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AB is a midsegment of trapezoid DEFG what is x?

Mamont248 [21]

Answer:

D. 2

Step-by-step explanation:

DEFG is a trapezoid and AB is its Midsegment.

Therefore,

$AB =\frac{1}{2}(DG + EF) \\ \\ 12 = \frac{1}{2} (5x - 4 + 8x + 2) \\ \\ 12 \times 2= (13x - 2) \\ \\ 24 = 13x - 2 \\ \\ 24 + 2 = 13x \\ \\ 26 = 13x \\ \\ x = \frac{26}{13} \\ \\ x = 2$

5 0

2 years ago

Suppose you'd like to save enough money to pay cash for your next car. The goal is to save an extra $28,000 over the next 6 year

Anna35 [415]

Given:

• Amount to save, A = $28,000

• Time, t = 6 years

• Interest rate, r = 5.3% ==> 0.053

• Number of times compounded = quarterly = 4 times

Let's find the amount that must be deposited into the account quarterly.

Apply the formula:

$FV=P(\frac{(1+\frac{r}{n})^{nt}-1}{\frac{r}{n}})$

Where:

FV is the future value = $28,000

r = 0.053

n = 4

t = 6 years

Thus, we have:

$28000=P(\frac{(1+\frac{0.053}{4})^{4\times6}-1)}{\frac{0.053}{4}}$

Let's solve for P.

We have:

$\begin{gathered} 28000=P(\frac{(1+0.01325)^{24}-1}{0.01325}) \\ \\ 28000=P(\frac{(1.01325)^{24}-1)^{}}{0.01325}) \\ \\ 28000=P(\frac{1.371509114-1}{0.01325}) \\ \\ 28000=P(\frac{0.371509114}{0.01325}) \end{gathered}$

Solving further: