A=WL
P=2(L+W)
A=(x)(14-x)
W=x
L=14-x
P=2((14-x)+x)
P=2(14-x+x)
P=2(14+0)
P=2(14)
P=28
perimiter=24 units
Answer:
There is no possible triangles
Step-by-step explanation:
\frac{\sin A}{a}=\frac{\sin B}{b}
a
sinA
=
b
sinB
From the reference sheet (reciprocal version).
\frac{\sin O}{58}=\frac{\sin 52}{13}
58
sinO
=
13
sin52
Plug in values.
\sin O=\frac{58\sin 52}{13}\approx 3.5157403
sinO=
13
58sin52
≈3.5157403O=\sin^{-1}(3.5157403)= \text{ERROR}
O=sin
−1
(3.5157403)=ERROR
Sine cannot be greater than 1.
{No Possible Triangles}
No Possible Triangles
{}
{}
The answer is 4 because the d is already negative
Answer:
Infintely many solutions
Step-by-step explanation:
I'm going to assume that the capital y is equal to the lowerase y
if you subtract y and two from both sides in the second equation you get
-y=2x-2
you then divide by -1 to get it into a normal form
y= -2x+2
this is the same as the first equation, these lines are the same
