Answer:
θ = 10.28º
Explanation:
To find the angle of refraction use the equation of refraction
n₁ sin θ₁ = n₂ sin θ₂
where index 1 is for incident light and index 2 is for refracted light.
sin θ₂ = n₁ / n₂ sin θ
let's calculate
sin = 1 / 1.3 sin 0.23
sin = 0.175
θ= 0.17528 rad
let's reduce to degrees
θ = 0.17528 rad (180ª / pi rad)
θ = 10.28º
You multiply force times friction
Answer:
The magnitude of the gravitational force is 4.53 * 10 ^-7 N
Explanation:
Given that the magnitude of the gravitational force is F = GMm/r²
mass M = 850 kg
mass m = 2.0 kg
distance d = 1.0 m , r = 0.5 m
F = GMm/r²
Gravitational Constant G = 6.67 × 10^-11 Newtons kg-2 m2.
F = (6.67 × 10^-11 * 850 * 2)/0.5²
F = 0.00000045356 N
F = 4.53 * 10 ^-7 N
Answer:
λ = 3.4 × 10^18m
Explanation:using Rydberg equation:
1/λ = RH •Z^2[ (1/n1) - (1/n2) ]
RH = Rydberg constant = 2.18x 10^-18j)
n1 and n2 = energy levels (n2 >n1)
Z = atomic number = 4
Substitute
1/λ = 2.18x 10^-18• [ (1/3) - (1/5) }
λ = 3.4 × 10^18m
