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DaniilM [7]
3 years ago
7

A box weighing 200N is pushed on a horizontal floor. What acceleration will result if a horizontal force of 100N is applied on t

he box. Coefficient of sliding friction is 0.4
Physics
2 answers:
blagie [28]3 years ago
8 0

Answer:

The acceleration of the block is 0.98 m/s².

Explanation:

It is given that,

Weight of a box, W = 200 N

Horizontal force acting on the box, F = 100 N

Coefficient of sliding friction is 0.4

Net force acting on the box, F_{net}=F-\mu W    

F_{net}=100-0.4\times 200  

F_{net}=20\ N  

Let a is the acceleration of the box. So,

a=\dfrac{F_{net}}{m}

Since, m=\dfrac{W}{g}=\dfrac{200}{9.8}=20.40\ kg

a=\dfrac{20}{20.40}

a=0.98\ m/s^2

So, the acceleration of the block is 0.98 m/s². Hence, this is the required solution.

Bogdan [553]3 years ago
4 0

Answer:

the friction force in the reverse direction is 200 *0.4=80 N.

the net forward force acting on the box is therefore

Fnet= 100 - 80  N

= 20 N

acceleration = Fnet / mass

=Fnet *g/(weight)

=20 *9.8/200 = 0.98 m/s^2

Explanation:

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A wave traveling in water has a frequency of 250 Hz and a wavelength of 6.0 N. What is the speed of the wave?
enyata [817]
The speed of a wave is determined by the product of the frequency and the wavelength; we already have the wavelength and the frequency, so all we need to do is multiply them by each other and use our proper unit of measure.

Velocity (speed) = Frequency x Wavelength
V = 250 x 6
V = 1500

Your answer is 1500 m/s.

I hope this helps!
5 0
3 years ago
L 10. A car with a mass of 2,000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. The
garri49 [273]
Centripetal Force, F = mv²/r

Where m = mass in kg, v = velocity in m/s and r = radius of curvature in m.

Centripetal Force, F = 2000 * 25² / 80.    Use your calculator.

                           F = 15 625 N.
3 0
3 years ago
Describe a situation in which an object's speed is constant but its velocity is changing.
Olegator [25]
1) If the object changes directions with the same speed, it will be changing its velocity, because velocity is a vector, which depends on both magnitude and direction. Speed is just magnitude regardless of direction.

2) Rotational motion. 
5 0
3 years ago
A box is lowered using a rope. If the acceleration of the box, is 3.3 m/s2 (downward) and its mass is 29.1 kg, what is the magni
Stells [14]

Answer:

T=189.15 N

Explanation:

As we know that for downward motion

F acting = F (weight) - Tension T

m a = mg - T

⇒ T = m (g - a)

T = 29.1 kg ( 9.8 m/s² - 3.3 m/s²)

T=189.15 N

8 0
3 years ago
So far in your life, you may have assumed that as you are sitting in your chair right now, you are not accelerating. However, th
shutvik [7]

Answer:

Answer is explained in the explanation section.

Explanation:

A)

Solution:

For this to find, we need to calculate the centripetal acceleration on the equator.

The centripetal acceleration of the equator:

a = 4\pi ^{2}RcosФ/T^{2},

where,

R is the radius of the earth

R = 6378 KM = 6.3 x 10^{6} and

T is the time period

T = 24 h = 86164.1 s

At Equator, Ф = 0°

So, CosФ = 1

Hence,

a = 4\pi ^{2}R/T^{2}

By plugging in the values, we get:

a = 4 x (3.14^{2}) x (6.3 x 10^{6}) / 86164.1^{2}

a = 0.03 m/s^{2}

Hence, this is the centripetal acceleration on the equator. And we also know that, acceleration due to gravity is 9.8 m/s^{2} which is very higher than the centripetal acceleration on the equator.

B) Normal force exerted by chair will always be equal and opposite to the mass times gravitational acceleration (F = mg). Otherwise, I would be thrown away from chair in case the normal force is not equal and opposite or I would be drag down to the earth due to greater mass times gravitational acceleration. Hence, both are equal and opposite.

C) Of course, this is not a lie, it is true because the acceleration due to gravity is 9.8 m/ s^{2} and as we calculated the acceleration on the equator is 0.03 m/s^{2} which way too low to experience.

For percentage difference,

9.8 - 0.03 = 9.77

So, % diff = (9.8 - 9.77)/9.8 x 100

% diff = 0.00306 x 100

% diff = 0.306%

Obviously, this is way too low to experience.

D) With the help of same formula as discussed above, we have:

a = 4\pi ^{2}RcosФ/T^{2},

Here, Ф = 44.4°

Just putting the values. we get

a = 0.0241 m/s^{2}

Acceleration while sitting in my chair.

6 0
2 years ago
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