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DaniilM [7]
3 years ago
7

A box weighing 200N is pushed on a horizontal floor. What acceleration will result if a horizontal force of 100N is applied on t

he box. Coefficient of sliding friction is 0.4
Physics
2 answers:
blagie [28]3 years ago
8 0

Answer:

The acceleration of the block is 0.98 m/s².

Explanation:

It is given that,

Weight of a box, W = 200 N

Horizontal force acting on the box, F = 100 N

Coefficient of sliding friction is 0.4

Net force acting on the box, F_{net}=F-\mu W    

F_{net}=100-0.4\times 200  

F_{net}=20\ N  

Let a is the acceleration of the box. So,

a=\dfrac{F_{net}}{m}

Since, m=\dfrac{W}{g}=\dfrac{200}{9.8}=20.40\ kg

a=\dfrac{20}{20.40}

a=0.98\ m/s^2

So, the acceleration of the block is 0.98 m/s². Hence, this is the required solution.

Bogdan [553]3 years ago
4 0

Answer:

the friction force in the reverse direction is 200 *0.4=80 N.

the net forward force acting on the box is therefore

Fnet= 100 - 80  N

= 20 N

acceleration = Fnet / mass

=Fnet *g/(weight)

=20 *9.8/200 = 0.98 m/s^2

Explanation:

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