1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DaniilM [7]
3 years ago
7

A box weighing 200N is pushed on a horizontal floor. What acceleration will result if a horizontal force of 100N is applied on t

he box. Coefficient of sliding friction is 0.4
Physics
2 answers:
blagie [28]3 years ago
8 0

Answer:

The acceleration of the block is 0.98 m/s².

Explanation:

It is given that,

Weight of a box, W = 200 N

Horizontal force acting on the box, F = 100 N

Coefficient of sliding friction is 0.4

Net force acting on the box, F_{net}=F-\mu W    

F_{net}=100-0.4\times 200  

F_{net}=20\ N  

Let a is the acceleration of the box. So,

a=\dfrac{F_{net}}{m}

Since, m=\dfrac{W}{g}=\dfrac{200}{9.8}=20.40\ kg

a=\dfrac{20}{20.40}

a=0.98\ m/s^2

So, the acceleration of the block is 0.98 m/s². Hence, this is the required solution.

Bogdan [553]3 years ago
4 0

Answer:

the friction force in the reverse direction is 200 *0.4=80 N.

the net forward force acting on the box is therefore

Fnet= 100 - 80  N

= 20 N

acceleration = Fnet / mass

=Fnet *g/(weight)

=20 *9.8/200 = 0.98 m/s^2

Explanation:

You might be interested in
The vector position of an object is given by r what is the torque acting on the object about the origin when a force f = (−12.5i
attashe74 [19]
Let the vector position of the object in the (x-y) plane be 
\vec{r} = x \hat{i} + y \hat{j}

The applied force is
\vec{f} = -12.5 \hat{i}


By definition, the applied torque is
\vec{T} = \vec{r} \times \vec{f} = (x\hat{i} + y\hat{j}) \times (-12.5y \hat{i}) = 12.5\hat{k}

Answer: 12.5y \, \hat{k}

7 0
3 years ago
How much potintial energy is in a closed system where the height of the object is 2 m, and the mass is 10 kg?
Lorico [155]

Answer:

D. 196 J

Explanation:

PE=mgh=10×9.8×2=196J

6 0
2 years ago
Read 2 more answers
Objects with masses of 165 kg and a 465 kg are separated by 0.340 m. (a) Find the net gravitational force exerted by these objec
Dmitrij [34]

Answer:

(a) F_{net} = 4.19 x 10^{-5} N, and its direction is towards m_{2}.

(b) It must be placed inside a hollow shell.

Explanation:

Let, m_{1} = 165 kg, m_{2} = 465 kg, m_{3} = 60 kg, and the distance between m_{1} and m_{2} is 0.340 m.

(a) Since m_{3} is placed midway between m_{1} and m_{2}, then its distance to both masses is 0.170 m.

From the Newton's law of universal gravitation,

F = \frac{Gm_{1}m_{2}  }{r^{2} }

Where all variables have their usual meaning.

Then,

a. F_{net} = F_{23} - F_{13}

F_{13} = \frac{6.67*10^{-11}*165*60 }{(0.17)^{2} }

     = 2.25 x 10^{-5} N

F_{23} = \frac{6.67*10^{-11}*465*60 }{(0.17)^{2} }

     = 6.44 x 10^{-5} N

∴ F_{net} =  = 6.44 x 10^{-5} - 2.25 x 10^{-5}

              = 4.19 x 10^{-5} N

The net force exerted by the two masses on the 60 kg object is 4.19 x 10^{-5}  N.

(ii) /F_{net}/ = /F_{23}/ - /F_{13}/

              = 6.44 x 10^{-5} - 2.25 x 10^{-5}

              = 4.19 x 10^{-5} N

(iii) The direction of the net force is to the right i.e towards m_{2}.

(b) For the net force experienced by the 60 kg object to be zero, it must be placed inside a hollow shell.

7 0
3 years ago
Remy wonders if the height of the mountain has anything to do with the eventual size of the tsunami wave. How should Remy test t
Anna71 [15]

Answer:

<em>The answer is B</em>

Explanation:

<em>I got this from study island</em>

5 0
3 years ago
A superhero swings a magic hammer over her head in a horizontal plane. The end of the hammer moves around a circular path of rad
Korolek [52]

Answer:

9.21954 m/s

54 m/s²

Angle is zero

Explanation:

r = Radius of arm = 1.5 m

\omega = Angular velocity = 6 rad/s

The horizontal component of speed is given by

v_h=\omega r\\\Rightarrow v_h=6\times 1.5\\\Rightarrow v_h=9\ m/s

The vertical component of speed is given by

v_v=2\ m/s

The resultant of the two components will give us the velocity of hammer with respect to the ground

v=\sqrt{v_h^2+v_v^2}\\\Rightarrow v=\sqrt{9^2+2^2}\\\Rightarrow v=9.21954\ m/s

The velocity of hammer relative to the ground is 9.21954 m/s

Acceleration in the vertical component is zero

Net acceleration is given by

a_n=a_h=\omega^2r\\\Rightarrow a_n=6^2\times 1.5\\\Rightarrow a_n=54\ m/s^2

Net acceleration is 54 m/s²

As the acceleration is towards the center the angle is zero.

3 0
2 years ago
Other questions:
  • What kinds of space and matter can light travel through
    5·2 answers
  • In refraction, when a wave travels from one medium to another, it
    10·2 answers
  • Julia and her musician friends were competing in the school talent show. Julia wanted her band to win the "most talented" award,
    8·2 answers
  • A thin layer of liquid methylene iodide (n = 1.756) is sandwiched between two flat, parallel plates of glass (n = 1.50). What mu
    7·1 answer
  • Groundwater is desirable for which of the following reasons?
    9·1 answer
  • What was the main cause of the shift to a postindustrial society?
    9·1 answer
  • A bus covers 10 km in 7 minutes. Find the speed of the bus in km/h
    14·1 answer
  • A 10248 kg car is pulled by a low tow truck that has an acceleration of 2.0m/s what is the net force on the car
    15·1 answer
  • What is the Gravitational Potential Energy of a 30 kg box lifted 1.5 meters off the ground?
    7·1 answer
  • Unit Test Review
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!