Question

A box weighing 200N is pushed on a horizontal floor. What acceleration will result if a horizontal force of 100N is applied on the box. Coefficient of sliding friction is 0.4

Answer 1

Answer:

The acceleration of the block is 0.98 m/s².

Explanation:

It is given that,

Weight of a box, W = 200 N

Horizontal force acting on the box, F = 100 N

Coefficient of sliding friction is 0.4

Net force acting on the box, $F_{net}=F-\mu W$    

$F_{net}=100-0.4\times 200$  

$F_{net}=20\ N$  

Let a is the acceleration of the box. So,

$a=\dfrac{F_{net}}{m}$

Since, $m=\dfrac{W}{g}=\dfrac{200}{9.8}=20.40\ kg$

$a=\dfrac{20}{20.40}$

$a=0.98\ m/s^2$

So, the acceleration of the block is 0.98 m/s². Hence, this is the required solution.

Answer 2

Answer:

the friction force in the reverse direction is 200 *0.4=80 N.

the net forward force acting on the box is therefore

Fnet= 100 - 80  N

= 20 N

acceleration = Fnet / mass

=Fnet *g/(weight)

=20 *9.8/200 = 0.98 m/s^2

Explanation: