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Maru [420]
3 years ago
13

When a radioactive atom emits an alpha particle, the mass number of the radioactive atom

Chemistry
2 answers:
ANTONII [103]3 years ago
8 0

Answer:

c

Explanation:

did it

arlik [135]3 years ago
5 0

Answer:

d or c

Explanation:

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In your own words, describe chromosomes, genes, and DNA.
FinnZ [79.3K]
A gene is the basic unit of heredity, DNA a self replicating material and chromosome a structure of nucleic acids and protein.
4 0
3 years ago
What is the mass of 4.40 moles of magnesium chloride, MgCl2?
Darya [45]
Since the number of moles of a substance is the mass divided by the molar mass of the substance, we can just simply multiply the molar mass of magnesium chloride by the number of moles, which is 4.40 in this case.

To find the molar mass, refer to the periodic table for the relative atomic mass of Mg and Cl and add them together. Since there’s 2 chloride ions in MgCl2, double the relative atomic mass of Cl when adding.

24.31 + 35.45x2
=95.21

Now just multiply 95.21 to 4.40mol, which you’ll get 418.9g (corrected to 3 significant figures)
3 0
3 years ago
Copper(II) fluoride contains 37.42% F by mass. Calculate the mass of fluorine (in g) in 55.5 g of copper(II) fluoride.
Mrac [35]

Answer:

There are 20.8 g of fluorine in 55.5 g of copper (II) fluoride

Explanation:

x % by mass of a species in a specimen means there are x g of the species in total 100 g of a specimen

37.42 % F by mass means 100 g of copper (II) fluoride contains 37.42 g of F.

So, 100 g of copper (II) fluoride contains 37.42 g of F

55.5 g of copper (II) fluoride contains \frac{37.42\times 55.5}{100}g of F or 20.8 g of F

Hence there are 20.8 g of fluorine in 55.5 g of copper (II) fluoride.

5 0
3 years ago
Even though the molecular formula of acetylene is C2H2, and that of benzene is C6H6, these compounds have the same percent compo
alexandr402 [8]

Answer:

CH

Explanation:

The empirical formular is the simplest formular of a compound. It shows the relative number of elements present in a compounds. It shows the number of atoms of elements present in simple ratios.

In both compounds, the ratio of the carbon to hydrogen s 1:1

In C2H2;

C : H = 2 : 2 (Which is equivalent to 1 : 1)

In C6H6;

C : H = 6 : 6 (Which is equivalent to 1 : 1)

This means the empirical formular is CH

7 0
3 years ago
¿Cual es la nomenclatura del sodio?
Shtirlitz [24]

Answer:

Nomenclatura de sodio

nomenclatura de compuestos iónicos En compuesto químico: Compuestos iónicos que contienen iones poliatómicos ... el compuesto NaOH se llama hidróxido de sodio, ya que contiene el catión Na+ (sodio) y el anión OH (hidróxido).

Explanation:

3 0
2 years ago
Read 2 more answers
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